使用泛型:

func Keys[K comparable, V any](m map[K]V) []K {
    keys := make([]K, 0, len(m))

    for k := range m {
        keys = append(keys, k)
    }

    return keys
}

类型不可知的解决方案:

for _, key := range reflect.ValueOf(yourMap).MapKeys() {
    value := yourMap.MapIndex(key).Interface()
    fmt.Println("Key:", key, "Value:", value)
}  

有没有一种方法可以在Go语言映射中获得所有键的列表?

ks := reflect.ValueOf(m).MapKeys()

如何遍历所有键?

使用公认的答案:

for _, k := range m { ... }

用于映射[string]字符串的排序键。

package main

import (
    "fmt"
    "sort"
)

func main() {
    m := map[string]string{"key1": "val1", "key2": "val2"}
    sortStringMap(m)
}

// sortStringMap prints the [string]string as keys sorted
func sortStringMap(m map[string]string) {
    var keys []string
    for key := range m {
        keys = append(keys, key)
    }
    sort.Strings(keys)  // sort the keys
    for _, key := range keys {
        fmt.Printf("%s\t:%s\n", key, m[key])
    }
}

输出:

key1    :val1
key2    :val2

使用泛型:

func Keys[K comparable, V any](m map[K]V) []K {
    keys := make([]K, 0, len(m))

    for k := range m {
        keys = append(keys, k)
    }

    return keys
}

这里有一些简单的方法来获得地图键的切片。

// Return keys of the given map
func Keys(m map[string]interface{}) (keys []string) {
    for k := range m {
        keys = append(keys, k)
    }
    return keys
}

// use `Keys` func
func main() {
    m := map[string]interface{}{
        "foo": 1,
        "bar": true,
        "baz": "baz",
    }
    fmt.Println(Keys(m)) // [foo bar baz]
}