你可以听漂亮。

侦听器

interface PermissionListener {
    fun onNeedPermission()
    fun onPermissionPreviouslyDenied(numberDenyPermission: Int)
    fun onPermissionDisabledPermanently(numberDenyPermission: Int)
    fun onPermissionGranted()
}

MainClass的权限

class PermissionUtil {

    private val PREFS_FILENAME = "permission"
    private val TAG = "PermissionUtil"

    private fun shouldAskPermission(context: Context, permission: String): Boolean {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            val permissionResult = ActivityCompat.checkSelfPermission(context, permission)
            if (permissionResult != PackageManager.PERMISSION_GRANTED) {
                return true
            }
        }
        return false
    }

    fun checkPermission(context: Context, permission: String, listener: PermissionListener) {

        Log.i(TAG, "CheckPermission for $permission")

        if (shouldAskPermission(context, permission)) {

            // Load history permission
            val sharedPreference = context.getSharedPreferences(PREFS_FILENAME, 0)
            val numberShowPermissionDialog = sharedPreference.getInt(permission, 0)

            if (numberShowPermissionDialog == 0) {

                (context as? Activity)?.let {
                    if (ActivityCompat.shouldShowRequestPermissionRationale(it, permission)) {
                        Log.e(TAG, "User has denied permission but not permanently")
                        listener.onPermissionPreviouslyDenied(numberShowPermissionDialog)
                    } else {
                        Log.e(TAG, "Permission denied permanently.")
                        listener.onPermissionDisabledPermanently(numberShowPermissionDialog)
                    }
                } ?: kotlin.run {
                    listener.onNeedPermission()
                }

            } else {
                // Is FirstTime
                listener.onNeedPermission()
            }


            // Save history permission
            sharedPreference.edit().putInt(permission, numberShowPermissionDialog + 1).apply()


        } else {
            listener.onPermissionGranted()
        }

    }
}

以这种方式使用

      PermissionUtil().checkPermission(this, Manifest.permission.ACCESS_FINE_LOCATION,
                object : PermissionListener {
                    override fun onNeedPermission() {
                        log("---------------------->onNeedPermission")

//                            ActivityCompat.requestPermissions(this@SplashActivity,
//                                    Array(1) { Manifest.permission.ACCESS_FINE_LOCATION },
//                                    118)

                    }

                    override fun onPermissionPreviouslyDenied(numberDenyPermission: Int) {
                        log("---------------------->onPermissionPreviouslyDenied")
                    }

                    override fun onPermissionDisabledPermanently(numberDenyPermission: Int) {
                        log("---------------------->onPermissionDisabled")
                    }

                    override fun onPermissionGranted() {
                        log("---------------------->onPermissionGranted")
                    }

                })

在activity或fragmnet中覆盖onRequestPermissionsResult

override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
 if (requestCode == 118) {
        if (permissions[0] == Manifest.permission.ACCESS_FINE_LOCATION && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
            getLastLocationInMap()
        }
        }
    }

OnRequestPermissionResult-free和shouldshowrequestpermissionrationalfree方法:

public static void requestDangerousPermission(AppCompatActivity activity, String permission) {
        if (hasPermission(activity, permission)) return;
        requestPermission();

        new Handler().postDelayed(() -> {
            if (activity.getLifecycle().getCurrentState() == Lifecycle.State.RESUMED) {
                Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
                intent.setData(Uri.parse("package:" + context.getPackageName()));
                context.startActivity(intent);
            }
        }, 250);
    }

如果没有权限弹出，250ms后打开设备设置(如果选择了“Never ask again”，就是这种情况)。

我在Android m中写了一个权限请求的简写，这段代码还处理了对旧Android版本的向后兼容性。

所有丑陋的代码都被提取到一个片段中，该片段将自己附加到请求权限的活动上。PermissionRequestManager的使用方法如下:

new PermissionRequestManager()
        // We need a AppCompatActivity here, if you are not using support libraries you will have to slightly change 
        // the PermissionReuqestManager class
        .withActivity(this)

        // List all permissions you need
        .withPermissions(android.Manifest.permission.CALL_PHONE, android.Manifest.permission.READ_CALENDAR)

        // This Runnable is called whenever the request was successfull
        .withSuccessHandler(new Runnable() {
            @Override
            public void run() {
                // Do something with your permissions!
                // This is called after the user has granted all 
                // permissions, we are one a older platform where 
                // the user does not need to grant permissions 
                // manually, or all permissions are already granted

            }
        })

        // Optional, called when the user did not grant all permissions
        .withFailureHandler(new Runnable() {
            @Override
            public void run() {
                // This is called if the user has rejected one or all of the requested permissions
                L.e(this.getClass().getSimpleName(), "Unable to request permission");

            }
        })

        // After calling this, the user is prompted to grant the rights
        .request();

来看看:https://gist.github.com/crysxd/385b57d74045a8bd67c4110c34ab74aa

为了准确地回答这个问题，当用户按下“永不再问”时会发生什么?

重写的方法/函数

onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray)

grantResult数组显示为空，你可以在这里做些什么?但不是最好的做法。

如何处理“永不再问”?

我正在使用Fragment，它需要READ_EXTERNAL_STORAGE权限。

override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
        super.onViewCreated(view, savedInstanceState)

        when {
            isReadPermissionsGranted() -> {

                /**
                 * Permissions has been Granted
                 */

                getDirectories()
            }

            isPermissionDeniedBefore() -> {

                /**
                 * User has denied before, explain why we need the permission and ask again
                 */

                updateUIForDeniedPermissions()
                checkIfPermissionIsGrantedNow()

            }
            else -> {

                /**
                 * Need to ask For Permissions, First Time
                 */

                checkIfPermissionIsGrantedNow()

                /**
                 * If user selects, "Dont Ask Again" it will never ask again! so just update the UI for Denied Permissions
                 */

                updateUIForDeniedPermissions()

            }
        }
    }

其他的函数是微不足道的。

// Is Read Write Permissions Granted
fun isReadWritePermissionGranted(context: Context): Boolean {
    return (ContextCompat.checkSelfPermission(
        context as Activity,
        Manifest.permission.READ_EXTERNAL_STORAGE
    ) == PackageManager.PERMISSION_GRANTED) and
            (ContextCompat.checkSelfPermission(
                context,
                Manifest.permission.WRITE_EXTERNAL_STORAGE
            ) == PackageManager.PERMISSION_GRANTED)
}

fun isReadPermissionDenied(context: Context) : Boolean {
    return ActivityCompat.shouldShowRequestPermissionRationale(
        context as Activity,
        PermissionsUtils.READ_EXTERNAL_STORAGE_PERMISSIONS)
}

开发者预览2对应用程序请求权限的方式进行了一些更改(参见http://developer.android.com/preview/support.html#preview2-notes)。

第一个对话框现在看起来像这样:

没有“永不再次显示”复选框(不像开发人员预览1)。如果用户拒绝权限，如果权限是必不可少的应用程序，它可以显示另一个对话框来解释应用程序请求该权限的原因，例如:

如果用户再次拒绝，应用程序应该关闭(如果它绝对需要该权限)或继续运行有限的功能。如果用户重新考虑(并选择重试)，则再次请求权限。这次的提示符是这样的:

第二次显示“永不再问”复选框。如果用户再次拒绝并且勾选复选框，就不会再发生任何事情。 是否勾选复选框可以通过使用Activity.shouldShowRequestPermissionRationale(String)来确定，例如:

if (shouldShowRequestPermissionRationale(Manifest.permission.WRITE_CONTACTS)) {...

这就是Android文档所说的(https://developer.android.com/training/permissions/requesting.html):

To help find the situations where you need to provide extra explanation, the system provides the Activity.shouldShowRequestPermissionRationale(String) method. This method returns true if the app has requested this permission previously and the user denied the request. That indicates that you should probably explain to the user why you need the permission. If the user turned down the permission request in the past and chose the Don't ask again option in the permission request system dialog, this method returns false. The method also returns false if the device policy prohibits the app from having that permission.

要知道用户是否拒绝了“never ask again”，你可以再次检查你的onRequestPermissionsResult中的shouldShowRequestPermissionRationale方法，当用户没有授予权限时。

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    if (requestCode == REQUEST_PERMISSION) {
        // for each permission check if the user granted/denied them
        // you may want to group the rationale in a single dialog,
        // this is just an example
        for (int i = 0, len = permissions.length; i < len; i++) {
            String permission = permissions[i];
            if (grantResults[i] == PackageManager.PERMISSION_DENIED) {
            // user rejected the permission
                boolean showRationale = shouldShowRequestPermissionRationale( permission );
                if (! showRationale) {
                    // user also CHECKED "never ask again"
                    // you can either enable some fall back,
                    // disable features of your app
                    // or open another dialog explaining
                    // again the permission and directing to
                    // the app setting
                } else if (Manifest.permission.WRITE_CONTACTS.equals(permission)) {
                    showRationale(permission, R.string.permission_denied_contacts);
                    // user did NOT check "never ask again"
                    // this is a good place to explain the user
                    // why you need the permission and ask if he wants
                    // to accept it (the rationale)
                } else if ( /* possibly check more permissions...*/ ) {
                }
            }
        }
    }
}

你可以用下面的代码打开你的应用程序设置:

Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
Uri uri = Uri.fromParts("package", getPackageName(), null);
intent.setData(uri);
startActivityForResult(intent, REQUEST_PERMISSION_SETTING);

无法将用户直接发送到授权页面。

shouldShowRequestPermissionRationale()方法可以用来检查用户是否选择了“never asked again”选项并拒绝了权限。 有很多代码示例，所以我宁愿解释如何将它用于这样的目的，因为我认为它的名称和实现使它比实际情况更加复杂。

正如在运行时请求权限中解释的那样，如果选项“never ask again”可见，该方法返回true，否则返回false;因此，它在第一次显示对话框时返回false，然后从第二次开始返回true，只有当用户拒绝选择该选项的权限时，它才会再次返回false。

要检测这种情况，您可以检测序列false-true-false，或者(更简单)您可以使用一个标记来跟踪对话框显示的初始时间。在此之后，该方法返回true或false，其中false将允许您检测何时选择该选项。