我想为Firebase创建多个云功能，并从一个项目同时部署它们。我还想将每个函数分离到一个单独的文件中。目前，我可以创建多个函数，如果我把它们都放在index.js，如:
exports.foo = functions.database.ref('/foo').onWrite(event => {
...
});
exports.bar = functions.database.ref('/bar').onWrite(event => {
...
});
然而，我想把foo和酒吧在单独的文件。我试了一下:
/functions
|--index.js (blank)
|--foo.js
|--bar.js
|--package.json
foo.js在哪里
exports.foo = functions.database.ref('/foo').onWrite(event => {
...
});
bar.js是
exports.bar = functions.database.ref('/bar').onWrite(event => {
...
});
有没有一种方法可以在不把所有函数都放在index.js中的情况下实现这一点?
@jasonsirota的回答很有帮助。但是查看更详细的代码可能会有用，特别是在HTTP触发函数的情况下。
使用与@jasonsirota回答中相同的结构，假设你希望在两个不同的文件中有两个单独的HTTP触发函数:
目录结构:
/functions
|--index.js
|--foo.js
|--bar.js
|--package.json
index.js:
'use strict';
const fooFunction = require('./foo');
const barFunction = require('./bar');
// Note do below initialization tasks in index.js and
// NOT in child functions:
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
const database = admin.database();
// Pass database to child functions so they have access to it
exports.fooFunction = functions.https.onRequest((req, res) => {
fooFunction.handler(req, res, database);
});
exports.barFunction = functions.https.onRequest((req, res) => {
barFunction.handler(req, res, database);
});
foo.js:
exports.handler = function(req, res, database) {
// Use database to declare databaseRefs:
usersRef = database.ref('users');
...
res.send('foo ran successfully');
}
bar.js:
exports.handler = function(req, res, database) {
// Use database to declare databaseRefs:
usersRef = database.ref('users');
...
res.send('bar ran successfully');
}
我使用一个普通的JS引导加载器来自动包含我想使用的所有函数。
├── /functions
│ ├── /test/
│ │ ├── testA.js
│ │ └── testB.js
│ ├── index.js
│ └── package.json
index.js(引导)
/**
* The bootloader reads all directories (single level, NOT recursively)
* to include all known functions.
*/
const functions = require('firebase-functions');
const fs = require('fs')
const path = require('path')
fs.readdirSync(process.cwd()).forEach(location => {
if (!location.startsWith('.')) {
location = path.resolve(location)
if (fs.statSync(location).isDirectory() && path.dirname(location).toLowerCase() !== 'node_modules') {
fs.readdirSync(location).forEach(filepath => {
filepath = path.join(location, filepath)
if (fs.statSync(filepath).isFile() && path.extname(filepath).toLowerCase() === '.js') {
Object.assign(exports, require(filepath))
}
})
}
}
})
这个例子index.js文件只在根目录中自动包含目录。它可以扩展到walk目录，honor .gitignore等。不过这对我来说已经足够了。
有了索引文件，添加新函数就很简单了。
/测试/ testA.js
const functions = require('firebase-functions');
exports.helloWorld = functions.https.onRequest((request, response) => {
response.send("Hello from Firebase!");
});
/测试/ testB.js
const functions = require('firebase-functions');
exports.helloWorld2 = functions.https.onRequest((request, response) => {
response.send("Hello again, from Firebase!");
});
NPM运行服务产生:
λ ~/Workspace/Ventures/Author.io/Firebase/functions/ npm run serve
> functions@ serve /Users/cbutler/Workspace/Ventures/Author.io/Firebase/functions
> firebase serve --only functions
=== Serving from '/Users/cbutler/Workspace/Ventures/Author.io/Firebase'...
i functions: Preparing to emulate functions.
Warning: You're using Node.js v9.3.0 but Google Cloud Functions only supports v6.11.5.
✔ functions: helloWorld: http://localhost:5000/authorio-ecorventures/us-central1/helloWorld
✔ functions: helloWorld2: http://localhost:5000/authorio-ecorventures/us-central1/helloWorld2
这个工作流程基本上就是“编写并运行”，而不必在每次添加/修改/删除新函数/文件时修改index.js文件。
Firebase文档现在已经更新了一个多文件代码组织的好指南:
文档>云功能>写功能>组织功能
总结:
foo.js
const functions = require('firebase-functions');
exports.foo = functions.https.onRequest((request, response) => {
// ...
});
bar.js
const functions = require('firebase-functions');
exports.bar = functions.https.onRequest((request, response) => {
// ...
});
index.js
const foo = require('./foo');
const bar = require('./bar');
exports.foo = foo.foo;
exports.bar = bar.bar;
我有这个项目，它有后台函数和http函数。我还有用于单元测试的测试。CI/CD将使您在部署云功能时更加轻松
文件夹结构
|-- package.json
|-- cloudbuild.yaml
|-- functions
|-- index.js
|-- background
| |-- onCreate
| |-- index.js
|-- create.js
|
|-- http
| |-- stripe
| |-- index.js
| |-- payment.js
|-- utils
|-- firebaseHelpers.js
|-- test
|-- ...
|-- package.json
注意:utils/文件夹用于在函数之间共享代码
函数/ index.js
在这里，您可以导入所需的所有函数并声明它们。这里不需要逻辑。在我看来，这样更干净。
require('module-alias/register');
const functions = require('firebase-functions');
const onCreate = require('@background/onCreate');
const onDelete = require('@background/onDelete');
const onUpdate = require('@background/onUpdate');
const tours = require('@http/tours');
const stripe = require('@http/stripe');
const docPath = 'tours/{tourId}';
module.exports.onCreate = functions.firestore.document(docPath).onCreate(onCreate);
module.exports.onDelete = functions.firestore.document(docPath).onDelete(onDelete);
module.exports.onUpdate = functions.firestore.document(docPath).onUpdate(onUpdate);
module.exports.tours = functions.https.onRequest(tours);
module.exports.stripe = functions.https.onRequest(stripe);
CI / CD
每次将更改推送到回购时都进行持续集成和部署如何?你可以使用谷歌谷歌云构建。它是免费的，直到某个点:)检查这个链接。
。/ cloudbuild.yaml
steps:
- name: "gcr.io/cloud-builders/npm"
args: ["run", "install:functions"]
- name: "gcr.io/cloud-builders/npm"
args: ["test"]
- name: "gcr.io/${PROJECT_ID}/firebase"
args:
[
"deploy",
"--only",
"functions",
"-P",
"${PROJECT_ID}",
"--token",
"${_FIREBASE_TOKEN}"
]
substitutions:
_FIREBASE_TOKEN: nothing
在我努力实现@zaidfazil的解决方案时，我想出了以下方法(使用JavaScript，而不是TypeScript)。
multi.js
exports.onQuestionMultiCreate = functions.database
.ref("/questions-multi/{questionId}")
.onCreate(async (snapshot, context) => {
...
}
});
trueFalse.js
exports.onQuestionTrueFalseCreate = functions.database
.ref("/questions-truefalse/{questionId}")
.onCreate(async (snapshot, context) => {
...
}
});
index.js
const multi = require("./multi");
const trueFalse = require("./trueFalse");
module.exports = {
...multi,
...trueFalse
