org大纲是一个更简单的体系结构模式，可以将方法分离到不同的文件中，并在index.js文件中的一行中导出。

本示例中项目的架构如下:

projectDirectory

index.js podcast.js profile.js

index.js

const admin = require('firebase-admin');
const podcast = require('./podcast');
const profile = require('./profile');
admin.initializeApp();

exports.getPodcast = podcast.getPodcast();
exports.removeProfile = profile.removeProfile();

podcast.js

const functions = require('firebase-functions');

exports.getPodcast = () => functions.https.onCall(async (data, context) => {
      ...
      return { ... }
  });

同样的模式将用于概要文件中的removeProfile方法。

Firebase文档现在已经更新了一个多文件代码组织的好指南:

文档>云功能>写功能>组织功能

总结:

foo.js

const functions = require('firebase-functions');
exports.foo = functions.https.onRequest((request, response) => {
  // ...
});

bar.js

const functions = require('firebase-functions');
exports.bar = functions.https.onRequest((request, response) => {
  // ...
});

index.js

const foo = require('./foo');
const bar = require('./bar');
exports.foo = foo.foo;
exports.bar = bar.bar;

啊，Firebase负载节点模块的云函数通常，所以这是有效的

结构:

/functions
|--index.js
|--foo.js
|--bar.js
|--package.json

index.js:

const functions = require('firebase-functions');
const fooModule = require('./foo');
const barModule = require('./bar');

exports.foo = functions.database.ref('/foo').onWrite(fooModule.handler);
exports.bar = functions.database.ref('/bar').onWrite(barModule.handler);

foo.js:

exports.handler = (event) => {
    ...
};

bar.js:

exports.handler = (event) => {
    ...
};

为了保持简单(但能完成工作)，我个人是这样构造我的代码的。

布局

├── /src/                      
│   ├── index.ts               
│   ├── foo.ts           
│   ├── bar.ts
|   ├── db.ts           
└── package.json  

foo.ts

import * as functions from 'firebase-functions';
export const fooFunction = functions.database()......... {
    //do your function.
}

export const someOtherFunction = functions.database().......... {
    // do the thing.
}

bar.ts

import * as functions from 'firebase-functions';
export const barFunction = functions.database()......... {
    //do your function.
}

export const anotherFunction = functions.database().......... {
    // do the thing.
}

db.ts

import * as admin from 'firebase-admin';
import * as functions from 'firebase-functions';

export const firestore = admin.firestore();
export const realtimeDb = admin.database();

index.ts

import * as admin from 'firebase-admin';
import * as functions from 'firebase-functions';

admin.initializeApp(functions.config().firebase);
// above codes only needed if you use firebase admin

export * from './foo';
export * from './bar';

适用于任何嵌套级别的目录。也只需遵循目录中的模式即可。

这要归功于@zaidfazil的答案

在我努力实现@zaidfazil的解决方案时，我想出了以下方法(使用JavaScript，而不是TypeScript)。

multi.js

exports.onQuestionMultiCreate = functions.database
  .ref("/questions-multi/{questionId}")
  .onCreate(async (snapshot, context) => {
   ...
    }
  });

trueFalse.js

exports.onQuestionTrueFalseCreate = functions.database
  .ref("/questions-truefalse/{questionId}")
  .onCreate(async (snapshot, context) => {
   ...
    }
  });

index.js

const multi = require("./multi");
const trueFalse = require("./trueFalse");

module.exports = {
  ...multi,
  ...trueFalse

Node 8 LTS现在可以与Cloud/Firebase函数一起使用，您可以使用扩展操作符执行以下操作:

/ package.json

"engines": {
  "node": "8"
},

/ index.js

const functions = require("firebase-functions");
const admin = require("firebase-admin");
admin.initializeApp();

module.exports = {
  ...require("./lib/foo.js"),
  // ...require("./lib/bar.js") // add as many as you like
};

/lib/foo.js

const functions = require("firebase-functions");
const admin = require("firebase-admin");

exports.fooHandler = functions.database
  .ref("/food/{id}")
  .onCreate((snap, context) => {
    let id = context.params["id"];

    return admin
      .database()
      .ref(`/bar/${id}`)
      .set(true);
  });