我正在尝试从Windows中的命令行执行Java程序。这是我的代码:

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class CopyFile
{
    public static void main(String[] args)
    {

        InputStream inStream = null;
        OutputStream outStream = null;

        try
        {

            File afile = new File("input.txt");
            File bfile = new File("inputCopy.txt");

            inStream = new FileInputStream(afile);
            outStream = new FileOutputStream(bfile);

            byte[] buffer = new byte[1024];

            int length;
            // copy the file content in bytes
            while ((length = inStream.read(buffer)) > 0)
            {

                outStream.write(buffer, 0, length);

            }

            inStream.close();
            outStream.close();

            System.out.println("File is copied successful!");

        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
    }
}

我不知道如何执行这个程序——有什么帮助吗?这在Windows上可行吗?为什么它与其他环境不同(我以为JVM是一次编写,随处运行)?


当前回答

假设文件名为“CopyFile.java”,执行以下操作:

javac CopyFile.java
java -cp . CopyFile

第一行将源代码编译为可执行的字节代码。第二行执行它,首先将当前目录添加到类路径(以防万一)。

其他回答

从Java 9开始,JDK包含了jshell,一个Java REPL。

假设JDK 9+ bin目录被正确地添加到您的路径中,您将能够简单地:

运行jshell file .java - file .java当然是你的文件。 将打开一个提示符,允许您调用main方法:jshell> File.main(null)。 要关闭提示符并结束JVM会话,请使用/exit

JShell的完整文档可以在这里找到。

假设文件名为“CopyFile.java”,执行以下操作:

javac CopyFile.java
java -cp . CopyFile

第一行将源代码编译为可执行的字节代码。第二行执行它,首先将当前目录添加到类路径(以防万一)。

在Windows 7上,我必须执行以下操作:

快速的方法

Install JDK http://www.oracle.com/technetwork/java/javase/downloads in windows, browse into "C:\Program Files\Java\jdk1.8.0_91\bin" (or wherever the latest version of JDK is installed), hold down shift and right click on a blank area within the window and do "open command window here" and this will give you a command line and access to all the BIN tools. "javac" is not by default in the windows system PATH environment variable. Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872

漫长的道路

Install JDK http://www.oracle.com/technetwork/java/javase/downloads/index.html After installing, in edits the Windows PATH environment variable and adds the following to the path C:\ProgramData\Oracle\Java\javapath. Within this folder are symbolic links to a handful of java executables but "javac" is NOT one of them so when trying to run "javac" from Windows command line it throws an error. I edited the path: Control Panel -> System -> Advanced tab -> "Environment Variables..." button -> scroll down to "Path", highlight and edit -> replaced the "C:\ProgramData\Oracle\Java\javapath" with a direct path to the java BIN folder "C:\Program Files\Java\jdk1.8.0_91\bin". This likely breaks when you upgrade your JDK installation but you have access to all the command line tools now. Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872

来源:javaindos。

Let's say your file is in C:\mywork\ Run Command Prompt C:\> cd \mywork This makes C:\mywork the current directory. C:\mywork> dir This displays the directory contents. You should see filenamehere.java among the files. C:\mywork> set path=%path%;C:\Program Files\Java\jdk1.5.0_09\bin This tells the system where to find JDK programs. C:\mywork> javac filenamehere.java This runs javac.exe, the compiler. You should see nothing but the next system prompt... C:\mywork> dir javac has created the filenamehere.class file. You should see filenamehere.java and filenamehere.class among the files. C:\mywork> java filenamehere This runs the Java interpreter. You should then see your program output. If the system cannot find javac, check the set path command. If javac runs but you get errors, check your Java text. If the program compiles but you get an exception, check the spelling and capitalization in the file name and the class name and the java HelloWorld command. Java is case-sensitive!

您实际上可以像运行shell或python脚本一样运行Java程序,而无需手动编译Java文件,如中所述 中330。它从JDK 11开始提供。

如果您创建了一个测试文件,并放入以下内容,您应该能够将其作为命令测试运行。您需要使用chmod +x测试使其在Linux和Mac OSX中可执行。

    #!/usr/bin/env java --source 11
    public class Test {
        public static void main(String [] args) {
            System.out.println("Hello world!");
            System.exit(0);
        }
    }

在前面的例子中,不允许使用.java文件扩展名。

    $ chmod +x testing
    $ ./testing
    Hello world!
    $

但是如果它的名称是Test.java,没有shebang“#!”前缀,你仍然可以执行,就像这样:

    public class Test {
        public static void main(String [] args) {
            System.out.println("Hello again!");
            System.exit(0);
        }
    }

然后使用以下命令执行Test.java文件:

    $ java Test.java
    Hello again!
    $

所以只要你在路径中有一个新的Java编译器,这就可以工作,用Java -version检查。更多信息请见本博客。