我需要一个选择,它将返回如下结果:
SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 word2 word3'
我需要所有的结果,即这包括字符串'word2 word3 word1'或'word1 word3 word2'或任何其他组合的三个。
结果中必须包含所有的单词。
我需要一个选择,它将返回如下结果:
SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 word2 word3'
我需要所有的结果,即这包括字符串'word2 word3 word1'或'word1 word3 word2'或任何其他组合的三个。
结果中必须包含所有的单词。
当前回答
相当缓慢,但工作方法包括任何单词:
SELECT * FROM mytable
WHERE column1 LIKE '%word1%'
OR column1 LIKE '%word2%'
OR column1 LIKE '%word3%'
如果你需要所有的单词都出现,使用这个:
SELECT * FROM mytable
WHERE column1 LIKE '%word1%'
AND column1 LIKE '%word2%'
AND column1 LIKE '%word3%'
如果您想要更快,您需要研究全文搜索,这对于每种数据库类型都是非常特定的。
其他回答
Use:
SELECT * FROM MyTable WHERE Column1 Like "*word*"
这将显示column1的部分值包含word的所有记录。
MySQL:
配套功能
-- Split @str by @sep
-- Returns all parts
CREATE FUNCTION [dbo].[fnSplit] (
@sep CHAR(1),
@str VARCHAR(512)
) RETURNS TABLE AS RETURN (
WITH Pieces(pn, start, stop) AS (
SELECT
1,
1,
CHARINDEX(@sep, @str)
UNION ALL
SELECT
pn + 1,
stop + 1,
CHARINDEX(@sep, @str, stop + 1)
FROM Pieces
WHERE stop > 0
)
SELECT
pn AS Id,
SUBSTRING(@str, start, CASE
WHEN stop > 0
THEN stop - start
ELSE 512
END) AS Data
FROM Pieces
)
查询示例
在MyTable中搜索单词word1, word2, word3。Column1:
-- Create a temporal table (the Data size depends on the length of the word)
DECLARE @FilterTable TABLE (Data VARCHAR(512))
-- Get different and unique words for the search
INSERT INTO @FilterTable (Data)
SELECT DISTINCT S.Data
FROM fnSplit(' ', 'word1 word2 word3') S -- Contains words
-- Search into "MyTable" by "Column1"
SELECT DISTINCT
T.*
FROM
MyTable T
-- Matching records
INNER JOIN @FilterTable F1 ON T.Column1 LIKE '%' + F1.Data + '%'
-- Is some word not present?
LEFT JOIN @FilterTable F2 ON T.Column1 NOT LIKE '%' + F2.Data + '%'
WHERE
-- Is some word not present?
F2.Data IS NULL;
注意,如果使用LIKE来确定一个字符串是否是另一个字符串的子字符串,则必须转义搜索字符串中的匹配字符的模式。
如果你的SQL方言支持CHARINDEX,那么使用它会更容易:
SELECT * FROM MyTable
WHERE CHARINDEX('word1', Column1) > 0
AND CHARINDEX('word2', Column1) > 0
AND CHARINDEX('word3', Column1) > 0
另外,请记住,这和接受的答案中的方法只涵盖子字符串匹配,而不是单词匹配。因此,例如,字符串'word1word2word3'仍然会匹配。
用"in"代替:
Select *
from table
where columnname in (word1, word2, word3)
DECLARE @SearchStr nvarchar(100)
SET @SearchStr = ' '
CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))
SET NOCOUNT ON
DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
SET @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')
WHILE @TableName IS NOT NULL
BEGIN
SET @ColumnName = ''
SET @TableName =
(
SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE'
AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
AND OBJECTPROPERTY(
OBJECT_ID(
QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
), 'IsMSShipped'
) = 0
)
WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
BEGIN
SET @ColumnName =
(
SELECT MIN(QUOTENAME(COLUMN_NAME))
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = PARSENAME(@TableName, 2)
AND TABLE_NAME = PARSENAME(@TableName, 1)
AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int', 'decimal')
AND QUOTENAME(COLUMN_NAME) > @ColumnName
)
IF @ColumnName IS NOT NULL
BEGIN
INSERT INTO #Results
EXEC
(
'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) FROM ' + @TableName + ' (NOLOCK) ' +
' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
)
END
END
END
SELECT ColumnName, ColumnValue FROM #Results
DROP TABLE #Results