我需要一个选择,它将返回如下结果:
SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 word2 word3'
我需要所有的结果,即这包括字符串'word2 word3 word1'或'word1 word3 word2'或任何其他组合的三个。
结果中必须包含所有的单词。
我需要一个选择,它将返回如下结果:
SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 word2 word3'
我需要所有的结果,即这包括字符串'word2 word3 word1'或'word1 word3 word2'或任何其他组合的三个。
结果中必须包含所有的单词。
当前回答
如果你只是想找到匹配。
SELECT * FROM MyTable WHERE INSTR('word1 word2 word3', Column1)<>0
SQL服务器:
CHARINDEX(Column1, 'word1 word2 word3', 1)<>0
得到精确匹配。例子:(ab;;;交流;,;b)将不会匹配。
SELECT * FROM MyTable WHERE INSTR(';word1;word2;word3;', ';'||Column1||';')<>0
其他回答
MySQL:
配套功能
-- Split @str by @sep
-- Returns all parts
CREATE FUNCTION [dbo].[fnSplit] (
@sep CHAR(1),
@str VARCHAR(512)
) RETURNS TABLE AS RETURN (
WITH Pieces(pn, start, stop) AS (
SELECT
1,
1,
CHARINDEX(@sep, @str)
UNION ALL
SELECT
pn + 1,
stop + 1,
CHARINDEX(@sep, @str, stop + 1)
FROM Pieces
WHERE stop > 0
)
SELECT
pn AS Id,
SUBSTRING(@str, start, CASE
WHEN stop > 0
THEN stop - start
ELSE 512
END) AS Data
FROM Pieces
)
查询示例
在MyTable中搜索单词word1, word2, word3。Column1:
-- Create a temporal table (the Data size depends on the length of the word)
DECLARE @FilterTable TABLE (Data VARCHAR(512))
-- Get different and unique words for the search
INSERT INTO @FilterTable (Data)
SELECT DISTINCT S.Data
FROM fnSplit(' ', 'word1 word2 word3') S -- Contains words
-- Search into "MyTable" by "Column1"
SELECT DISTINCT
T.*
FROM
MyTable T
-- Matching records
INNER JOIN @FilterTable F1 ON T.Column1 LIKE '%' + F1.Data + '%'
-- Is some word not present?
LEFT JOIN @FilterTable F2 ON T.Column1 NOT LIKE '%' + F2.Data + '%'
WHERE
-- Is some word not present?
F2.Data IS NULL;
最好的方法是在表中的列上创建全文索引 用contains代替LIKE
SELECT * FROM MyTable WHERE
contains(Column1, N'word1')
AND contains(Column1, N'word2')
AND contains(Column1, N'word3')
注意,如果使用LIKE来确定一个字符串是否是另一个字符串的子字符串,则必须转义搜索字符串中的匹配字符的模式。
如果你的SQL方言支持CHARINDEX,那么使用它会更容易:
SELECT * FROM MyTable
WHERE CHARINDEX('word1', Column1) > 0
AND CHARINDEX('word2', Column1) > 0
AND CHARINDEX('word3', Column1) > 0
另外,请记住,这和接受的答案中的方法只涵盖子字符串匹配,而不是单词匹配。因此,例如,字符串'word1word2word3'仍然会匹配。
select * from table where name regexp '^word[1-3]$'
or
select * from table where name in ('word1','word2','word3')
用"in"代替:
Select *
from table
where columnname in (word1, word2, word3)