如果你只是想找到匹配。

SELECT * FROM MyTable WHERE INSTR('word1 word2 word3', Column1)<>0

SQL服务器:

CHARINDEX(Column1, 'word1 word2 word3', 1)<>0

得到精确匹配。例子:(ab;;;交流;,;b)将不会匹配。

SELECT * FROM MyTable WHERE INSTR(';word1;word2;word3;', ';'||Column1||';')<>0

Use:

SELECT * FROM MyTable WHERE Column1 Like "*word*"

这将显示column1的部分值包含word的所有记录。

注意，如果使用LIKE来确定一个字符串是否是另一个字符串的子字符串，则必须转义搜索字符串中的匹配字符的模式。

如果你的SQL方言支持CHARINDEX，那么使用它会更容易:

SELECT * FROM MyTable
WHERE CHARINDEX('word1', Column1) > 0
  AND CHARINDEX('word2', Column1) > 0
  AND CHARINDEX('word3', Column1) > 0

另外，请记住，这和接受的答案中的方法只涵盖子字符串匹配，而不是单词匹配。因此，例如，字符串'word1word2word3'仍然会匹配。

将SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 word2 word3'替换为在这些单词之间添加And:

SELECT * FROM MyTable WHERE Column1 CONTAINS 'word1 And word2 And word3'

详细信息请参见CONTAINS (Transact-SQL)。

在选择短语时，使用双引号:

SELECT * FROM MyTable WHERE Column1 CONTAINS '"Phrase one" And word2 And "Phrase Two"'

附注:在使用contains关键字之前，您必须首先在表上启用全文检索。有关更多详细信息，请参见全文搜索入门。

MySQL:

配套功能

-- Split @str by @sep
-- Returns all parts
CREATE FUNCTION [dbo].[fnSplit] (
  @sep CHAR(1),
  @str VARCHAR(512)
) RETURNS TABLE AS RETURN (
  WITH Pieces(pn, start, stop) AS (
    SELECT
      1,
      1,
      CHARINDEX(@sep, @str)
    UNION ALL
    SELECT
      pn + 1,
      stop + 1,
      CHARINDEX(@sep, @str, stop + 1)
    FROM Pieces
    WHERE stop > 0
  )

  SELECT
    pn AS Id,
    SUBSTRING(@str, start, CASE
      WHEN stop > 0
      THEN stop - start
      ELSE 512
    END) AS Data
  FROM Pieces
)

查询示例

在MyTable中搜索单词word1, word2, word3。Column1:

-- Create a temporal table (the Data size depends on the length of the word)
DECLARE @FilterTable TABLE (Data VARCHAR(512))

-- Get different and unique words for the search
INSERT INTO @FilterTable (Data)
SELECT DISTINCT S.Data
FROM fnSplit(' ', 'word1 word2 word3') S -- Contains words

-- Search into "MyTable" by "Column1"
SELECT DISTINCT
  T.*
FROM
  MyTable T
  -- Matching records
  INNER JOIN @FilterTable F1 ON T.Column1 LIKE '%' + F1.Data + '%'
  -- Is some word not present?
  LEFT JOIN @FilterTable F2 ON T.Column1 NOT LIKE '%' + F2.Data + '%'
WHERE
  -- Is some word not present?
  F2.Data IS NULL;

select * from table where name regexp '^word[1-3]$'

or

select * from table where name in ('word1','word2','word3')