用这个代码——

function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");

}

尽管这不是最简单的方法，但你可以这样做:

var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
    keys = "name address1 address2 city state zipcode".split(" "),
    address = {};

// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
    address[ keys.unshift() ] = match;
});

// address will contain the mapped result
address = {
    address1: "123 Street"
    address2: "Apt 4"
    city: "New York"
    name: "john smith"
    state: "NY"
    zipcode: "12345"
}

更新ES2015，使用解构

const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);

// The variables defined above now contain the appropriate information:

console.log(address1, address2, city, name, state, zipcode);
// -> john smith 123 Street Apt 4 New York NY 12345

嗯，最简单的方法是:

var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]

尝试使用纯Javascript

 //basic url=http://localhost:58227/ExternalApproval.html?Status=1

 var ar= [url,statu] = window.location.href.split("=");

你可以使用split来拆分文本。

作为替代，你也可以使用match，如下所示

var str = 'john smith~123 Street~Apt 4~New York~NY~12345'; 匹配= str.match(/[^~]+/g); console.log(匹配); document . write(匹配);

正则表达式[^~]+将匹配除~之外的所有字符，并在数组中返回匹配的字符。然后可以从中提取匹配项。

您需要研究JavaScript的substr或split，因为这不是一个真正适合jQuery的任务。