对这个替代方案有什么意见吗?

SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
sdf.format(date1).equals(sdf.format(date2));

我不知道这是新的想法或其他，但我给你展示我所做的

SimpleDateFormat dtf = new SimpleDateFormat("dd/MM/yyyy");
Date td_date = new Date();
String first_date = dtf.format(td_date);    //First seted in String 
String second_date = "30/11/2020";          //Second date you can set hear in String

String result = (first_date.equals(second_date)) ? "Yes, Its Equals":"No, It is not Equals";
System.out.println(result);

只需结合YEAR属性检查DAY_OF_YEAR

boolean isSameDay = 
firstCal.get(Calendar.YEAR) == secondCal.get(Calendar.YEAR) &&
firstCal.get(Calendar.DAY_OF_YEAR) == secondCal.get(Calendar.DAY_OF_YEAR)

编辑:

现在我们可以使用Kotlin扩展函数的强大功能

fun Calendar.isSameDay(second: Calendar): Boolean {

    return this[Calendar.YEAR] == second[Calendar.YEAR] && this[Calendar.DAY_OF_YEAR] == second[Calendar.DAY_OF_YEAR]
}

fun Calendar.compareDatesOnly(other: Calendar): Int {

    return when {
        isSameDay(other) -> 0
        before(other) -> -1
        else -> 1
    }
}

对这个替代方案有什么意见吗?

SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
sdf.format(date1).equals(sdf.format(date2));

我的建议:

    Calendar cal = Calendar.getInstance();
    cal.set(1999,10,01);   // nov 1st, 1999
    cal.set(Calendar.AM_PM,Calendar.AM);
    cal.set(Calendar.HOUR,0);
    cal.set(Calendar.MINUTE,0);
    cal.set(Calendar.SECOND,0);
    cal.set(Calendar.MILLISECOND,0);

    // date column in the Thought table is of type sql date
    Thought thought = thoughtDao.getThought(date, language);

    Assert.assertEquals(cal.getTime(), thought.getDate());

Apache commons-lang几乎无处不在。那么这个呢?

if (DateUtils.isSameDay(date1, date2)) {
    // it's same
} else if (date1.before(date2)) {
   // it's before
} else {
   // it's after
}