我通过比较时间戳来解决这个问题:

    Calendar last = Calendar.getInstance();

    last.setTimeInMillis(firstTimeInMillis);

    Calendar current = Calendar.getInstance();

    if (last.get(Calendar.DAY_OF_MONTH) != current.get(Calendar.DAY_OF_MONTH)) {
        //not the same day
    }

我避免使用Joda Time，因为在Android上占用很大的空间。规模很重要。,)

public static Date getZeroTimeDate(Date fecha) {
    Date res = fecha;
    Calendar calendar = Calendar.getInstance();

    calendar.setTime( fecha );
    calendar.set(Calendar.HOUR_OF_DAY, 0);
    calendar.set(Calendar.MINUTE, 0);
    calendar.set(Calendar.SECOND, 0);
    calendar.set(Calendar.MILLISECOND, 0);

    res = calendar.getTime();

    return res;
}

Date currentDate = getZeroTimeDate(new Date());// get current date   

这是解决这个问题最简单的方法。

已经提到了apache common -utils:

org.apache.commons.lang.time.DateUtils.truncate(date, Calendar.DAY_OF_MONTH)

给你Date对象，只包含日期，没有时间，你可以与Date. compareto进行比较

我不知道这是新的想法或其他，但我给你展示我所做的

SimpleDateFormat dtf = new SimpleDateFormat("dd/MM/yyyy");
Date td_date = new Date();
String first_date = dtf.format(td_date);    //First seted in String 
String second_date = "30/11/2020";          //Second date you can set hear in String

String result = (first_date.equals(second_date)) ? "Yes, Its Equals":"No, It is not Equals";
System.out.println(result);

public Date saveDateWithoutTime(Date date) {
    Calendar calendar = Calendar.getInstance();

    calendar.setTime( date );
    calendar.set(Calendar.HOUR_OF_DAY, 0);
    calendar.set(Calendar.HOUR, 0);
    calendar.set(Calendar.MINUTE, 0);
    calendar.set(Calendar.SECOND, 0);
    calendar.set(Calendar.MILLISECOND, 0);

    return calendar.getTime();
}

这将帮助你在不考虑时间的情况下比较日期。

`

SimpleDateFormat sdf= new SimpleDateFormat("MM/dd/yyyy")

   Date date1=sdf.parse("03/25/2015");



  Date currentDate= sdf.parse(sdf.format(new Date()));

   return date1.compareTo(currentDate);

`