你可以更新你的JPARepository，如下所示。

@Query("select u.status from UserLogin u where u.userId = ?1 or u.email = ?1 or u.mobile = ?1")
public UserStatus findByUserIdOrEmailOrMobile(String loginId);

UserStatus为Enum

public enum UserStatus
{
    New,
    Active,
    Deactived,
    Suspended,
    Locked
}

在我看来，这是一个很好的解决方案:

interface PersonRepository extends Repository<Person, UUID> {

    <T> Collection<T> findByLastname(String lastname, Class<T> type);
}

像这样使用它

void someMethod(PersonRepository people) {

  Collection<Person> aggregates =
    people.findByLastname("Matthews", Person.class);

  Collection<NamesOnly> aggregates =
    people.findByLastname("Matthews", NamesOnly.class);
}

你可以在Repository类的@Query注释中设置nativeQuery = true，如下所示:

public static final String FIND_PROJECTS = "SELECT projectId, projectName FROM projects";

@Query(value = FIND_PROJECTS, nativeQuery = true)
public List<Object[]> findProjects();

请注意，您必须自己进行映射。使用常规的映射查找可能会更简单，除非你真的只需要这两个值:

public List<Project> findAll()

Spring数据文档可能也值得一看。

public static final String FIND_PROJECTS = "select ac_year_id,ac_year from tbl_au_academic_year where ac_year_id=?1";

    @Query(value = FIND_PROJECTS, nativeQuery = true)
    public  List<Object[]> findByAcYearId(Integer ac_year_id);

这对我很有用

使用本机查询:

Query query = entityManager.createNativeQuery("SELECT projectId, projectName FROM projects");
List result = query.getResultList();

你可以使用JPQL:

TypedQuery <Object[]> query = em.createQuery(
  "SELECT p.projectId, p.projectName FROM projects AS p", Object[].class);

List<Object[]> results = query.getResultList();

或者您可以使用本地SQL查询。

Query query = em.createNativeQuery("sql statement");
List<Object[]> results = query.getResultList();