.title()方法不能很好地工作，

>>> "they're bill's friends from the UK".title()
"They'Re Bill'S Friends From The Uk"

试试string.capwords()方法，

import string
string.capwords("they're bill's friends from the UK")
>>>"They're Bill's Friends From The Uk"

来自Python capwords文档:

使用str.split()将参数拆分为单词，使用str.capitalize()将每个单词大写，并使用str.join()连接大写的单词。如果可选的第二个参数sep不存在或为None，则空白字符的运行将被单个空格替换，并且前导和尾部的空白将被删除，否则sep用于分隔和连接单词。

这里总结了不同的方法，以及一些需要注意的陷阱

它们将适用于所有这些输入:

""           => ""       
"a b c"      => "A B C"             
"foO baR"    => "FoO BaR"      
"foo    bar" => "Foo    Bar"   
"foo's bar"  => "Foo's Bar"    
"foo's1bar"  => "Foo's1bar"    
"foo 1bar"   => "Foo 1bar"     

Splitting the sentence into words and capitalizing the first letter then join it back together: # Be careful with multiple spaces, and empty strings # for empty words w[0] would cause an index error, # but with w[:1] we get an empty string as desired def cap_sentence(s): return ' '.join(w[:1].upper() + w[1:] for w in s.split(' ')) Without splitting the string, checking blank spaces to find the start of a word def cap_sentence(s): return ''.join( (c.upper() if i == 0 or s[i-1] == ' ' else c) for i, c in enumerate(s) ) Or using generators: # Iterate through each of the characters in the string # and capitalize the first char and any char after a blank space from itertools import chain def cap_sentence(s): return ''.join( (c.upper() if prev == ' ' else c) for c, prev in zip(s, chain(' ', s)) ) Using regular expressions, from steveha's answer: # match the beginning of the string or a space, followed by a non-space import re def cap_sentence(s): return re.sub("(^|\s)(\S)", lambda m: m.group(1) + m.group(2).upper(), s)

现在，这些是其他一些被发布的答案，如果我们将一个单词定义为句子的开头或空格后的任何东西，输入就不会像预期的那样工作:

.title () 返回s.title () #不需要的输出: "foO baR" => "foO baR" "foo's bar" => "foo's bar" "foo's1bar" => "foo's1bar" "foo 1bar" => "foo 1bar"

.capitalize()或.capwords() 返回' '.join(w.r esize () for s.split()中的w) #或 进口的字符串 返回string.capwords(年代) #不需要的输出: "foO baR" => "foO baR" "foo bar" => "foo bar" 使用' '作为分割将修复第二个输出，但不能修复第一个输出 返回' '.join(w.r esize () for w in s.s split(' ')) #或 进口的字符串 返回字符串。大写字符(s， ' ') #不需要的输出: "foO baR" => "foO baR"

.upper () 注意使用多个空格，这可以通过使用' '进行分割来修复(如答案顶部所示) 返回' ' . join (w [0] .upper () + w (1:) w s.split ()) #不需要的输出: "foo bar" => "foo bar"

在Python中，您可以使用title()方法将字符串中的每个单词大写:

string = "this is a test string"
capitalized_string = string.title()
print(capitalized_string)

输出:

This Is A Test String

你可以试试这个。简单而利落。

def cap_each(string):
    list_of_words = string.split(" ")

    for word in list_of_words:
        list_of_words[list_of_words.index(word)] = word.capitalize()

    return " ".join(list_of_words)

字符串的.title()方法(ASCII或Unicode都可以)这样做:

>>> "hello world".title()
'Hello World'
>>> u"hello world".title()
u'Hello World'

但是，请注意带有内嵌撇号的字符串，如文档中所述。

该算法使用一个简单的独立于语言的单词定义作为连续的字母组。这个定义在很多情况下都适用，但它意味着缩略词和所有格中的撇号形成了单词边界，这可能不是理想的结果: >>> "他们是比尔来自英国的朋友".title() “他们是比尔的英国朋友”

当解决方案简单而安全的时候，为什么你要用连接和for循环来使你的生活复杂化?

只要这样做:

string = "the brown fox"
string[0].upper()+string[1:]