我有两个shell脚本,a.sh和b.sh。
我如何从shell脚本a.sh调用b.sh ?
我有两个shell脚本,a.sh和b.sh。
我如何从shell脚本a.sh调用b.sh ?
当前回答
#!/bin/bash
# Here you define the absolute path of your script
scriptPath="/home/user/pathScript/"
# Name of your script
scriptName="myscript.sh"
# Here you execute your script
$scriptPath/$scriptName
# Result of script execution
result=$?
其他回答
首先,你必须包含你调用的文件:
#!/bin/bash
. includes/included_file.sh
然后像这样调用函数:
#!/bin/bash
my_called_function
从其他文件导入函数会有一些问题。 首先:您不需要执行此文件。最好不要这样做! 只需添加
. file
导入所有函数。所有这些都是在文件中定义的。 第二:你可以定义同名的函数。它将被覆盖。它是坏的。你可以那样宣布
declare -f new_function_name=old_function_name
and only after that do import. So you may call old function by new name. Third: You may import only full list of functions defined in file. If some not needed you may unset them. But if you rewrite your functions after unset they will be lost. But if you set reference to it as described above you may restore after unset with the same name. Finally In common procedure of import is dangerous and not so simple. Be careful! You may write script to do this more easier and safe. If you use only part of functions(not all) better split them in different files. Unfortunately this technique not made well in bash. In python for example and some other script languages it's easy and safe. Possible to make partial import only needed functions with its own names. We all want that in next bush versions will be done the same functionality. But now We must write many additional cod so as to do what you want.
#!/bin/bash
# Here you define the absolute path of your script
scriptPath="/home/user/pathScript/"
# Name of your script
scriptName="myscript.sh"
# Here you execute your script
$scriptPath/$scriptName
# Result of script execution
result=$?
只需在一行中添加您在终端中输入的任何内容来执行脚本! 例如:
#!bin/bash
./myscript.sh &
如果要执行的脚本不在同一目录下,请使用脚本的完整路径。 例如:“/ home / user /脚本目录/。/ myscript.sh &
chmod a+x /path/to/file-to-be-executed
那是我唯一需要的东西。一旦要执行的脚本像这样可执行,您(至少在我的情况下)在调用脚本时不需要任何其他额外的操作,如sh或./。
感谢@Nathan Lilienthal的评论