是否有方法将JSON内容反序列化为c#动态类型?为了使用DataContractJsonSerializer,最好跳过创建一堆类。
当前回答
简单的“字符串JSON数据”对象,无需任何第三方DLL文件:
WebClient client = new WebClient();
string getString = client.DownloadString("https://graph.facebook.com/zuck");
JavaScriptSerializer serializer = new JavaScriptSerializer();
dynamic item = serializer.Deserialize<object>(getString);
string name = item["name"];
//note: JavaScriptSerializer in this namespaces
//System.Web.Script.Serialization.JavaScriptSerializer
注意:也可以使用自定义对象。
Personel item = serializer.Deserialize<Personel>(getString);
其他回答
你可以扩展JavaScriptSerializer来递归复制它创建的字典来扩展对象,然后动态地使用它们:
static class JavaScriptSerializerExtensions
{
public static dynamic DeserializeDynamic(this JavaScriptSerializer serializer, string value)
{
var dictionary = serializer.Deserialize<IDictionary<string, object>>(value);
return GetExpando(dictionary);
}
private static ExpandoObject GetExpando(IDictionary<string, object> dictionary)
{
var expando = (IDictionary<string, object>)new ExpandoObject();
foreach (var item in dictionary)
{
var innerDictionary = item.Value as IDictionary<string, object>;
if (innerDictionary != null)
{
expando.Add(item.Key, GetExpando(innerDictionary));
}
else
{
expando.Add(item.Key, item.Value);
}
}
return (ExpandoObject)expando;
}
}
然后,您只需要为您在其中定义扩展的名称空间使用一个using语句(考虑在System.Web.Script.Serialization中定义它们…)另一个技巧是不使用命名空间,那么你根本不需要using语句),你可以像这样使用它们:
var serializer = new JavaScriptSerializer();
var value = serializer.DeserializeDynamic("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");
var name = (string)value.Name; // Jon Smith
var age = (int)value.Age; // 42
var address = value.Address;
var city = (string)address.City; // New York
var state = (string)address.State; // NY
我想在单元测试中以编程的方式完成,我可以把它打出来。
我的解决方案是:
var dict = JsonConvert.DeserializeObject<ExpandoObject>(json) as IDictionary<string, object>;
现在我可以断言
dict.ContainsKey("ExpectedProperty");
.NET 4.0有一个内置库可以做到这一点:
using System.Web.Script.Serialization;
JavaScriptSerializer jss = new JavaScriptSerializer();
var d = jss.Deserialize<dynamic>(str);
这是最简单的方法。
试试这种方法!
JSON的例子:
[{
"id": 140,
"group": 1,
"text": "xxx",
"creation_date": 123456,
"created_by": "xxx@gmail.co",
"tags": ["xxxxx"]
}, {
"id": 141,
"group": 1,
"text": "xxxx",
"creation_date": 123456,
"created_by": "xxx@gmail.com",
"tags": ["xxxxx"]
}]
c#代码:
var jsonString = (File.ReadAllText(Path.Combine(Directory.GetCurrentDirectory(),"delete_result.json")));
var objects = JsonConvert.DeserializeObject<dynamic>(jsonString);
foreach(var o in objects)
{
Console.WriteLine($"{o.id.ToString()}");
}
我做了一个使用Expando对象的DynamicJsonConverter的新版本。我使用了expando对象,因为我想使用Json.NET将动态序列化回JSON。
using System;
using System.Collections;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Dynamic;
using System.Web.Script.Serialization;
public static class DynamicJson
{
public static dynamic Parse(string json)
{
JavaScriptSerializer jss = new JavaScriptSerializer();
jss.RegisterConverters(new JavaScriptConverter[] { new DynamicJsonConverter() });
dynamic glossaryEntry = jss.Deserialize(json, typeof(object)) as dynamic;
return glossaryEntry;
}
class DynamicJsonConverter : JavaScriptConverter
{
public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
{
if (dictionary == null)
throw new ArgumentNullException("dictionary");
var result = ToExpando(dictionary);
return type == typeof(object) ? result : null;
}
private static ExpandoObject ToExpando(IDictionary<string, object> dictionary)
{
var result = new ExpandoObject();
var dic = result as IDictionary<String, object>;
foreach (var item in dictionary)
{
var valueAsDic = item.Value as IDictionary<string, object>;
if (valueAsDic != null)
{
dic.Add(item.Key, ToExpando(valueAsDic));
continue;
}
var arrayList = item.Value as ArrayList;
if (arrayList != null && arrayList.Count > 0)
{
dic.Add(item.Key, ToExpando(arrayList));
continue;
}
dic.Add(item.Key, item.Value);
}
return result;
}
private static ArrayList ToExpando(ArrayList obj)
{
ArrayList result = new ArrayList();
foreach (var item in obj)
{
var valueAsDic = item as IDictionary<string, object>;
if (valueAsDic != null)
{
result.Add(ToExpando(valueAsDic));
continue;
}
var arrayList = item as ArrayList;
if (arrayList != null && arrayList.Count > 0)
{
result.Add(ToExpando(arrayList));
continue;
}
result.Add(item);
}
return result;
}
public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{
throw new NotImplementedException();
}
public override IEnumerable<Type> SupportedTypes
{
get { return new ReadOnlyCollection<Type>(new List<Type>(new[] { typeof(object) })); }
}
}
}
推荐文章
- HTTP POST返回错误:417“期望失败。”
- 如何在。net中创建和使用资源
- 为什么Path。以Path.DirectorySeparatorChar开头的文件名合并不正确?
- 如何在c#中获得正确的时间戳
- Linq选择列表中存在的对象(A,B,C)
- c# .NET中的App.config是什么?如何使用它?
- c#:如何获得一个字符串的第一个字符?
- String类中的什么方法只返回前N个字符?
- 我如何提高ASP。NET MVC应用程序性能?
- 更好的方法将对象转换为int类型
- 我可以将c#字符串值转换为转义字符串文字吗?
- 在c#中转换char到int
- c#中朋友的对等物是什么?
- 关键字使用virtual+override vs. new
- 无法解析类型为“Microsoft.AspNetCore.Http.IHttpContextAccessor”的服务