最简单的方法是:

只需包含这个DLL文件。

像这样使用代码:

dynamic json = new JDynamic("{a:'abc'}");
// json.a is a string "abc"

dynamic json = new JDynamic("{a:3.1416}");
// json.a is 3.1416m

dynamic json = new JDynamic("{a:1}");
// json.a is

dynamic json = new JDynamic("[1,2,3]");
/json.Length/json.Count is 3
// And you can use json[0]/ json[2] to get the elements

dynamic json = new JDynamic("{a:[1,2,3]}");
//json.a.Length /json.a.Count is 3.
// And you can use  json.a[0]/ json.a[2] to get the elements

dynamic json = new JDynamic("[{b:1},{c:1}]");
// json.Length/json.Count is 2.
// And you can use the  json[0].b/json[1].c to get the num.

使用DataSet(c#)和JavaScript。一个创建带有DataSet输入的JSON流的简单函数。创建JSON内容，如(多表数据集):

[[{a:1,b:2,c:3},{a:3,b:5,c:6}],[{a:23,b:45,c:35},{a:58,b:59,c:45}]]

只是客户端，使用eval。例如,

var d = eval('[[{a:1,b:2,c:3},{a:3,b:5,c:6}],[{a:23,b:45,c:35},{a:58,b:59,c:45}]]')

然后使用:

d[0][0].a // out 1 from table 0 row 0

d[1][1].b // out 59 from table 1 row 1

// Created by Behnam Mohammadi And Saeed Ahmadian
public string jsonMini(DataSet ds)
{
    int t = 0, r = 0, c = 0;
    string stream = "[";

    for (t = 0; t < ds.Tables.Count; t++)
    {
        stream += "[";
        for (r = 0; r < ds.Tables[t].Rows.Count; r++)
        {
            stream += "{";
            for (c = 0; c < ds.Tables[t].Columns.Count; c++)
            {
                stream += ds.Tables[t].Columns[c].ToString() + ":'" +
                          ds.Tables[t].Rows[r][c].ToString() + "',";
            }
            if (c>0)
                stream = stream.Substring(0, stream.Length - 1);
            stream += "},";
        }
        if (r>0)
            stream = stream.Substring(0, stream.Length - 1);
        stream += "],";
    }
    if (t>0)
        stream = stream.Substring(0, stream.Length - 1);
    stream += "];";
    return stream;
}

最简单的方法是:

只需包含这个DLL文件。

像这样使用代码:

dynamic json = new JDynamic("{a:'abc'}");
// json.a is a string "abc"

dynamic json = new JDynamic("{a:3.1416}");
// json.a is 3.1416m

dynamic json = new JDynamic("{a:1}");
// json.a is

dynamic json = new JDynamic("[1,2,3]");
/json.Length/json.Count is 3
// And you can use json[0]/ json[2] to get the elements

dynamic json = new JDynamic("{a:[1,2,3]}");
//json.a.Length /json.a.Count is 3.
// And you can use  json.a[0]/ json.a[2] to get the elements

dynamic json = new JDynamic("[{b:1},{c:1}]");
// json.Length/json.Count is 2.
// And you can use the  json[0].b/json[1].c to get the num.

c#有一个轻量级JSON库，叫做SimpleJson。

它支持。net 3.5+， Silverlight和Windows Phone 7。

它支持。net 4.0的动态

它也可以作为NuGet包安装

Install-Package SimpleJson

JsonFx可以将JSON内容反序列化为动态对象。

序列化动态类型(.NET 4.0的默认值):

var reader = new JsonReader(); var writer = new JsonWriter();

string input = @"{ ""foo"": true, ""array"": [ 42, false, ""Hello!"", null ] }";
dynamic output = reader.Read(input);
Console.WriteLine(output.array[0]); // 42
string json = writer.Write(output);
Console.WriteLine(json); // {"foo":true,"array":[42,false,"Hello!",null]}

你可以使用System.Web.Helpers.Json——它的Decode方法返回一个动态对象，你可以随意遍历它。

它包含在System.Web.Helpers程序集中(。NET 4.0)。

var dynamicObject = Json.Decode(jsonString);