如何在Flask中提供静态文件

So this is embarrassing. I've got an application that I threw together in Flask and for now it is just serving up a single static HTML page with some links to CSS and JS. And I can't find where in the documentation Flask describes returning static files. Yes, I could use render_template but I know the data is not templatized. I'd have thought send_file or url_for was the right thing, but I could not get those to work. In the meantime, I am opening the files, reading content, and rigging up a Response with appropriate mimetype:

import os.path

from flask import Flask, Response


app = Flask(__name__)
app.config.from_object(__name__)


def root_dir():  # pragma: no cover
    return os.path.abspath(os.path.dirname(__file__))


def get_file(filename):  # pragma: no cover
    try:
        src = os.path.join(root_dir(), filename)
        # Figure out how flask returns static files
        # Tried:
        # - render_template
        # - send_file
        # This should not be so non-obvious
        return open(src).read()
    except IOError as exc:
        return str(exc)


@app.route('/', methods=['GET'])
def metrics():  # pragma: no cover
    content = get_file('jenkins_analytics.html')
    return Response(content, mimetype="text/html")


@app.route('/', defaults={'path': ''})
@app.route('/<path:path>')
def get_resource(path):  # pragma: no cover
    mimetypes = {
        ".css": "text/css",
        ".html": "text/html",
        ".js": "application/javascript",
    }
    complete_path = os.path.join(root_dir(), path)
    ext = os.path.splitext(path)[1]
    mimetype = mimetypes.get(ext, "text/html")
    content = get_file(complete_path)
    return Response(content, mimetype=mimetype)


if __name__ == '__main__':  # pragma: no cover
    app.run(port=80)

有人愿意给出一个代码示例或url吗?我知道这非常简单。

当前回答

使用重定向和url_for

from flask import redirect, url_for

@app.route('/', methods=['GET'])
def metrics():
    return redirect(url_for('static', filename='jenkins_analytics.html'))

这个服务器在你的html中引用的所有文件(css & js…)

2015-12-28 22:21:59

其他回答

想到分享....这个例子。

from flask import Flask
app = Flask(__name__)

@app.route('/loading/')
def hello_world():
    data = open('sample.html').read()    
    return data

if __name__ == '__main__':
    app.run(host='0.0.0.0')

这样工作起来更好，也更简单。

2018-10-03 14:01:09

例如，要返回我使用过的Adsense文件:

@app.route('/ads.txt')
def send_adstxt():
    return send_from_directory(app.static_folder, 'ads.txt')

2022-02-17 19:44:02

最简单的方法是在主项目文件夹中创建一个静态文件夹。包含。css文件的静态文件夹。

主文件夹

/Main Folder
/Main Folder/templates/foo.html
/Main Folder/static/foo.css
/Main Folder/application.py(flask script)

图像的主文件夹包含静态和模板文件夹和烧瓶脚本

瓶

from flask import Flask, render_template

app = Flask(__name__)

@app.route("/")
def login():
    return render_template("login.html")

html(布局)

<!DOCTYPE html>
<html>
    <head>
        <title>Project(1)</title>
        <link rel="stylesheet" href="/static/styles.css">
     </head>
    <body>
        <header>
            <div class="container">
                <nav>
                    <a class="title" href="">Kamook</a>
                    <a class="text" href="">Sign Up</a>
                    <a class="text" href="">Log In</a>
                </nav>
            </div>
        </header>  
        {% block body %}
        {% endblock %}
    </body>
</html>

html

{% extends "layout.html" %}

{% block body %}
    <div class="col">
        <input type="text" name="username" placeholder="Username" required>
        <input type="password" name="password" placeholder="Password" required>
        <input type="submit" value="Login">
    </div>
{% endblock %}

2019-10-18 00:53:52

我遇到的问题与使用static_url_path和static_folder时没有为目录提供index.html文件有关。

以下是我的解决方案:

import os
from flask import Flask, send_from_directory
from flask.helpers import safe_join

app = Flask(__name__)
static = safe_join(os.path.dirname(__file__), 'static')

@app.route('/')
def _home():
  return send_from_directory(static, 'index.html')

@app.route('/<path:path>')
def _static(path):
  if os.path.isdir(safe_join(static, path)):
    path = os.path.join(path, 'index.html')
  return send_from_directory(static, path)

2021-10-11 17:32:46

静态文件的URL可以使用静态端点创建，如下所示:

url_for('static', filename = 'name_of_file')
<link rel="stylesheet" href="{{url_for('static', filename='borders.css')}}" />

2020-07-21 10:39:17

如何在Flask中提供静态文件

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