我正在用HTML和JavaScript设计一个正则表达式测试器。用户将输入一个正则表达式,一个字符串,并通过单选按钮选择他们想要测试的函数(例如搜索,匹配,替换等),当该函数以指定的参数运行时,程序将显示结果。自然会有额外的文本框用于替换额外的参数等等。

My problem is getting the string from the user and turning it into a regular expression. If I say that they don't need to have //'s around the regex they enter, then they can't set flags, like g and i. So they have to have the //'s around the expression, but how can I convert that string to a regex? It can't be a literal since its a string, and I can't pass it to the RegExp constructor since its not a string without the //'s. Is there any other way to make a user input string into a regex? Will I have to parse the string and flags of the regex with the //'s then construct it another way? Should I have them enter a string, and then enter the flags separately?


当前回答

使用RegExp对象构造函数从字符串创建正则表达式:

var re = new RegExp("a|b", "i");
// same as
var re = /a|b/i;

其他回答

下面是一个处理自定义分隔符和无效标志的线性函数

// One liner var stringToRegex = (s, m) => (m = s.match(/^([\/~@;%#'])(.*?)\1([gimsuy]*)$/)) ? new RegExp(m[2], m[3].split('').filter((i, p, s) => s.indexOf(i) === p).join('')) : new RegExp(s); // Readable version function stringToRegex(str) { const match = str.match(/^([\/~@;%#'])(.*?)\1([gimsuy]*)$/); return match ? new RegExp( match[2], match[3] // Filter redundant flags, to avoid exceptions .split('') .filter((char, pos, flagArr) => flagArr.indexOf(char) === pos) .join('') ) : new RegExp(str); } console.log(stringToRegex('/(foo)?\/bar/i')); console.log(stringToRegex('#(foo)?\/bar##gi')); //Custom delimiters console.log(stringToRegex('#(foo)?\/bar##gig')); //Duplicate flags are filtered out console.log(stringToRegex('/(foo)?\/bar')); // Treated as string console.log(stringToRegex('gig')); // Treated as string

你可以使用复选框来请求标志,然后做这样的事情:

var userInput = formInput;
var flags = '';
if(formGlobalCheckboxChecked) flags += 'g';
if(formCaseICheckboxChecked) flags += 'i';
var reg = new RegExp(userInput, flags);

这也适用于字符串无效或不包含标志等情况:

regExpFromString(q) { Let flags = q.replace(/.*\/([gimuy]*)$/, '$1'); If (flags === q) flags = "; Let pattern = (flags ?q.replace(新RegExp ('^/(.*?)/' + 旗帜 + '$'), '$ 1 '):问); try{返回新的RegExp(模式,标志);} catch (e){返回null;} } console.log (regExpFromString (' \ \ bword \ \ b ')); console.log (regExpFromString(‘\ / \ \ bword \ \ b \ / gi '));

我建议您还为特殊标志添加单独的复选框或文本框。这样很明显,用户不需要添加任何//。在替换的情况下,提供两个文本字段。这会让你的生活轻松很多。

为什么?因为否则一些用户会添加// s,而其他用户不会。有些会犯语法错误。然后,在去掉//之后,您可能会得到一个语法上有效的正则表达式,但它与用户想要的完全不同,从而导致奇怪的行为(从用户的角度来看)。

使用RegExp对象构造函数从字符串创建正则表达式:

var re = new RegExp("a|b", "i");
// same as
var re = /a|b/i;