在这个进程com.example.app中,我们看到了一些异常消息Default FirebaseApp is not initialized。确保首先调用FirebaseApp.initializeApp(Context)。在我们的Android应用中,我们刚刚添加了Firebase远程配置。

堆栈跟踪如下:

Fatal Exception: java.lang.IllegalStateException: Default FirebaseApp is not initialized in this process com.example.app. Make sure to call FirebaseApp.initializeApp(Context) first.
       at com.google.firebase.FirebaseApp.getInstance(Unknown Source)
       at com.google.firebase.remoteconfig.FirebaseRemoteConfig.getInstance(Unknown Source)
       at com.example.app.fragments.SomeFragment.updateFooter(SourceFile:295)
       at com.example.app.fragments.SomeFragment.onCreateView(SourceFile:205)
       at android.support.v4.app.Fragment.performCreateView(SourceFile:2080)
       at android.support.v4.app.FragmentManagerImpl.moveToState(SourceFile:1108)
       at android.support.v4.app.FragmentManagerImpl.moveToState(SourceFile:1290)
       at android.support.v4.app.BackStackRecord.run(SourceFile:801)
       at android.support.v4.app.FragmentManagerImpl.execSingleAction(SourceFile:1638)
       at android.support.v4.app.BackStackRecord.commitNowAllowingStateLoss(SourceFile:679)
       at android.support.v4.app.FragmentPagerAdapter.finishUpdate(SourceFile:143)
       at android.support.v4.view.ViewPager.populate(SourceFile:1240)
       at android.support.v4.view.ViewPager.populate(SourceFile:1088)
       at android.support.v4.view.ViewPager.setAdapter(SourceFile:542)
       at com.example.app.SomeActivity.onSomeAsyncCallback(SourceFile:908)
       at com.example.app.SomeDataRetriever.onAsyncHttpCompleted(SourceFile:72)
       at com.example.app.io.AsyncHttp.onPostExecute(SourceFile:141)
       at com.example.app.io.AsyncHttp.onPostExecute(SourceFile:19)
       at android.os.AsyncTask.finish(AsyncTask.java:679)
       at android.os.AsyncTask.access$500(AsyncTask.java:180)
       at android.os.AsyncTask$InternalHandler.handleMessage(AsyncTask.java:696)
       at android.os.Handler.dispatchMessage(Handler.java:102)
       at android.os.Looper.loop(Looper.java:150)
       at android.app.ActivityThread.main(ActivityThread.java:5665)
       at java.lang.reflect.Method.invoke(Method.java)
       at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:799)
       at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:689)

这是9.6.1版本,我们还使用了其他Firebase组件:

compile 'com.google.firebase:firebase-ads:9.6.1'
compile 'com.google.firebase:firebase-config:9.6.1'
compile 'com.google.firebase:firebase-invites:9.6.1'
compile "com.google.firebase:firebase-messaging:9.6.1"

正如我从文档和Javadoc中看到的,在我们的例子中,我们不应该做任何手动初始化。

这个异常发生在Android 4-6上的各种设备上。

编辑:

我发现这个问题引起了一些关注。我想这个解释对你们中的一些人来说可能很有趣:https://firebase.googleblog.com/2016/12/how-does-firebase-initialize-on-android.html


当前回答

我们必须在应用程序类的onCreate函数中初始化Firebase。

 package com.rocks.music.videoplayer;

 import android.app.Application;
 import android.content.Context;

 import com.google.firebase.FirebaseApp;


/**
* Created by ashish123 on 22/8/15.
  */
 public class MyApplication extends Application {

private static MyApplication mInstance;

@Override
public void onCreate() {
    super.onCreate();
    mInstance = this;
    try {
        FirebaseApp.initializeApp(this);
    }
    catch (Exception e) {
    }
}

public static Context getInstance() {
    return mInstance;
}

}

清单文件中的代码:-

  <application
    android:name="com.rocks.music.videoplayer.MyApplication"
    android:allowBackup="true"
    android:icon="@drawable/app_icon"
    android:label="@string/app_name"
    android:supportsRtl="true"
    android:theme="@style/AppTheme">

其他回答

对我来说,这是升级com.google的依赖关系。Gms:构建内部的google服务。gradle将

buildscript {
repositories {
    jcenter()
    mavenCentral()
    maven {
        url 'https://maven.google.com/'
        name 'Google'
    }
    google()
}
dependencies {
    classpath 'com.android.tools.build:gradle:3.3.2'
    classpath 'com.google.gms:google-services:4.2.0'

    // NOTE: Do not place your application dependencies here; they belong
    // in the individual module build.gradle files
}

我们必须在应用程序类的onCreate函数中初始化Firebase。

 package com.rocks.music.videoplayer;

 import android.app.Application;
 import android.content.Context;

 import com.google.firebase.FirebaseApp;


/**
* Created by ashish123 on 22/8/15.
  */
 public class MyApplication extends Application {

private static MyApplication mInstance;

@Override
public void onCreate() {
    super.onCreate();
    mInstance = this;
    try {
        FirebaseApp.initializeApp(this);
    }
    catch (Exception e) {
    }
}

public static Context getInstance() {
    return mInstance;
}

}

清单文件中的代码:-

  <application
    android:name="com.rocks.music.videoplayer.MyApplication"
    android:allowBackup="true"
    android:icon="@drawable/app_icon"
    android:label="@string/app_name"
    android:supportsRtl="true"
    android:theme="@style/AppTheme">

通过遵循@Gabriel Lidenor的回答,在我的情况下,初始化应用程序与上下文不工作。如果您试图创建没有google-service的firebase-app。json吗?所以在初始化任何数量的firebase应用程序之前,首先需要初始化为;

FirebaseOptions options = new FirebaseOptions.Builder().setApplicationId("APP_ID")
                    .setGcmSenderId("SENDER_ID").build();
FirebaseApp.initializeApp(context, options, "[DEFAULT]");

我解决这个问题: 应用插件:'com.google.gms。谷歌服务正在建设中。Gradle文件并移动文件google-service。Json在app文件夹下。

虽然手动初始化Firebase使用FirebaseApp.initializeApp(this);使错误消失,但不能修复根本原因,一些奇怪的问题聚集在一起似乎没有得到解决,例如

FCM需要com.google.android.c2dm.permission。接受许可 只适用于GCM 令牌在发送第一个通知后变为未注册 message not received/ onmessagerreceived()从未被调用,

使用更新的Gradle插件(例如Android插件2.2.3和Gradle 2.14.1)修复了所有问题。(当然设置必须是正确的,根据Firebase文档)