当关键字with已经发布时，此答案与Python-2.5以来的所有版本兼容。

1. 如果不存在则创建文件+设置当前时间 (与命令触摸完全相同)

import os

fname = 'directory/filename.txt'
with open(fname, 'a'):     # Create file if does not exist
    os.utime(fname, None)  # Set access/modified times to now
                           # May raise OSError if file does not exist

一个更健壮的版本:

import os

with open(fname, 'a'):
  try:                     # Whatever if file was already existing
    os.utime(fname, None)  # => Set current time anyway
  except OSError:
    pass  # File deleted between open() and os.utime() calls

2. 如果文件不存在，则创建该文件 (不更新时间)

with open(fname, 'a'):  # Create file if does not exist
    pass

3.只需更新文件访问/修改次数 (如果不存在，则不创建文件)

import os

try:
    os.utime(fname, None)  # Set access/modified times to now
except OSError:
    pass  # File does not exist (or no permission)

使用os.path.exists()不会简化代码:

from __future__ import (absolute_import, division, print_function)
import os

if os.path.exists(fname):
  try:
    os.utime(fname, None)  # Set access/modified times to now
  except OSError:
    pass  # File deleted between exists() and utime() calls
          # (or no permission)

奖励:更新目录中所有文件的时间

from __future__ import (absolute_import, division, print_function)
import os

number_of_files = 0

#   Current directory which is "walked through"
#   |     Directories in root
#   |     |  Files in root       Working directory
#   |     |  |                     |
for root, _, filenames in os.walk('.'):
  for fname in filenames:
    pathname = os.path.join(root, fname)
    try:
      os.utime(pathname, None)  # Set access/modified times to now
      number_of_files += 1
    except OSError as why:
      print('Cannot change time of %r because %r', pathname, why)

print('Changed time of %i files', number_of_files)

def touch(fname):
    if os.path.exists(fname):
        os.utime(fname, None)
    else:
        open(fname, 'a').close()

当关键字with已经发布时，此答案与Python-2.5以来的所有版本兼容。

1. 如果不存在则创建文件+设置当前时间 (与命令触摸完全相同)

import os

fname = 'directory/filename.txt'
with open(fname, 'a'):     # Create file if does not exist
    os.utime(fname, None)  # Set access/modified times to now
                           # May raise OSError if file does not exist

一个更健壮的版本:

import os

with open(fname, 'a'):
  try:                     # Whatever if file was already existing
    os.utime(fname, None)  # => Set current time anyway
  except OSError:
    pass  # File deleted between open() and os.utime() calls

2. 如果文件不存在，则创建该文件 (不更新时间)

with open(fname, 'a'):  # Create file if does not exist
    pass

3.只需更新文件访问/修改次数 (如果不存在，则不创建文件)

import os

try:
    os.utime(fname, None)  # Set access/modified times to now
except OSError:
    pass  # File does not exist (or no permission)

使用os.path.exists()不会简化代码:

from __future__ import (absolute_import, division, print_function)
import os

if os.path.exists(fname):
  try:
    os.utime(fname, None)  # Set access/modified times to now
  except OSError:
    pass  # File deleted between exists() and utime() calls
          # (or no permission)

奖励:更新目录中所有文件的时间

from __future__ import (absolute_import, division, print_function)
import os

number_of_files = 0

#   Current directory which is "walked through"
#   |     Directories in root
#   |     |  Files in root       Working directory
#   |     |  |                     |
for root, _, filenames in os.walk('.'):
  for fname in filenames:
    pathname = os.path.join(root, fname)
    try:
      os.utime(pathname, None)  # Set access/modified times to now
      number_of_files += 1
    except OSError as why:
      print('Cannot change time of %r because %r', pathname, why)

print('Changed time of %i files', number_of_files)

创建一个包含所需变量的字符串，并将其传递给os.system似乎是合乎逻辑的:

touch = 'touch ' + dir + '/' + fileName
os.system(touch)

这在很多方面是不够的(例如，它不能处理空白)，所以不要这样做。

一个更健壮的方法是使用subprocess:

子流程。([‘碰’,os.path打电话。加入(目录名,文件名)])

虽然这比使用subshell (os.system)要好得多，但它仍然只适用于快速和肮脏的脚本;使用跨平台程序的公认答案。

看起来这是Python 3.4的新功能- pathlib。

from pathlib import Path

Path('path/to/file.txt').touch()

这将在该路径下创建一个file.txt文件。

--

路径。触摸(模式= 0 o777 exist_ok = True) 在这个给定的路径上创建一个文件。如果给出了mode，它将与进程的umask值相结合，以确定文件模式和访问标志。如果文件已经存在，则如果exist_ok为true(并且其修改时间更新为当前时间)，则函数成功，否则将引发FileExistsError。

为什么不试试呢?：

import os

def touch(fname):
    try:
        os.utime(fname, None)
    except OSError:
        open(fname, 'a').close()

我相信这消除了任何重要的竞争条件。如果文件不存在，则会抛出异常。

这里唯一可能的竞态条件是，文件是在调用open()之前，但在os.utime()之后创建的。但这并不重要，因为在这种情况下，修改时间将如预期的那样，因为它必须发生在调用touch()期间。