在Python 3中，你可以这样做:

for item in range(1,10):
    print(item, end =" ")

输出:

1 2 3 4 5 6 7 8 9 

Tuple:你可以对Tuple做同样的事情:

tup = (1,2,3,4,5)

for n in tup:
    print(n, end = " - ")

输出:

1 - 2 - 3 - 4 - 5 - 

另一个例子:

list_of_tuples = [(1,2),('A','B'), (3,4), ('Cat', 'Dog')]
for item in list_of_tuples:
    print(item)

输出:

(1, 2)
('A', 'B')
(3, 4)
('Cat', 'Dog')

你甚至可以像这样解包你的元组:

list_of_tuples = [(1,2),('A','B'), (3,4), ('Cat', 'Dog')]

# Tuple unpacking so that you can deal with elements inside of the tuple individually
for (item1, item2) in list_of_tuples:
    print(item1, item2)   

输出:

1 2
A B
3 4
Cat Dog

另一个变化:

list_of_tuples = [(1,2),('A','B'), (3,4), ('Cat', 'Dog')]
for (item1, item2) in list_of_tuples:
    print(item1)
    print(item2)
    print('\n')

输出:

1
2


A
B


3
4


Cat
Dog

for item in range(1,100):
    if item==99:
        print(item,end='')
    else:
        print (item,end=',')

输出: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12、13、14、15、16、17、18、19日,20日,21日,22日,23日,24日,25日,26日,27日,28日,29、30、31、32、33、34、35、36、37、38、39、40、41、42、43、44、45、46岁,47岁,48岁,49岁,50岁,51岁,52岁,53岁,54岁,55岁,56岁,57岁,今年58岁,59岁,60岁,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99

打印语句末尾的逗号省略了新行。

for i in xrange(1,100):
  print i,

但这不会覆盖。

或者更简单:

import time
a = 0
while True:
    print (a, end="\r")
    a += 1
    time.sleep(0.1)

End ="\r"将覆盖第一次打印的开头[0:]。

和其他例子一样， 我使用类似的方法，但不是花时间计算最后的输出长度，等等，

我简单地使用ANSI代码转义移回行开始，然后在打印当前状态输出之前清除整行。

import sys

class Printer():
    """Print things to stdout on one line dynamically"""
    def __init__(self,data):
        sys.stdout.write("\r\x1b[K"+data.__str__())
        sys.stdout.flush()

为了在你的迭代循环中使用，你只需要调用如下代码:

x = 1
for f in fileList:
    ProcessFile(f)
    output = "File number %d completed." % x
    Printer(output)
    x += 1   

点击这里查看更多信息

对于那些像我一样挣扎的人，我提出了以下似乎在python 3.7.4和3.5.2中都可以工作的方法。

I expanded the range from 100 to 1,000,000 because it runs very fast and you may not see the output. This is because one side effect of setting end='\r' is that the final loop iteration clears all of the output. A longer number was needed to demonstrate that it works. This result may not be desirable in all cases, but was fine in mine, and OP didn't specify one way or another. You could potentially circumvent this with an if statement that evaluates the length of the array being iterated over, etc. The key to get it working in my case was to couple the brackets "{}" with .format(). Otherwise, it didn't work.

以下应按原样工作:

#!/usr/bin/env python3

for item in range(1,1000000):
    print("{}".format(item), end='\r', flush=True)