我写了这样的测试代码:
class MyProgram
{
int count = 0;
public static void main(String[] args)
{
System.out.println(count);
}
}
但它给出了以下错误:
Main.java:6: error: non-static variable count cannot be referenced from a static context
System.out.println(count);
^
我如何让我的方法识别我的类变量?
The first thing is to know the difference between an instance of a class, and the class itself. A class models certain properties, and the behaviour of the whole in the context of those properties. An instance will define specific values for those properties.
Anything bound to the static keyword is available in the context of the class rather than in the context of an instance of the class
As a corollary to the above
variables within a method can not be static
static fields, and methods must be invoked using the class-name e.g. MyProgram7.main(...)
The lifetime of a static field/method is equivalent to the lifetime of your application
如。
例如,汽车具有属性颜色,并表现出行为“运动”。
以25公里每小时的速度行驶的红色大众甲壳虫为例。
现在,汽车的静态属性将是道路上的车轮数量(4),这将适用于所有汽车。
HTH
让我们先分析一下你的程序。
在你的程序中,你的第一个方法是main(),记住它是静态方法…然后声明该方法的局部变量(comparate、low、high等)。这个变量的作用域只是声明的方法,不管它是静态方法还是非静态方法。你不能在这个方法之外使用这些变量。这是你犯的基本错误。
Then we come to next point. You told static is killing you. (It may be killing you but it only gives life to your program!!) First you must understand the basic thing.
*Static method calls only the static method and use only the static variable.
*Static variable or static method are not dependent on any instance of that class. (i.e. If you change any state of the static variable it will reflect in all objects of the class)
*Because of this you call it as a class variable or a class method.
And a lot more is there about the "static" keyword.
I hope now you get the idea. First change the scope of the variable and declare it as a static (to be able to use it in static methods).
给你们的建议是:你们误解了变量作用域和静态函数的概念。对此要有清晰的认识。