你可以使用LocalDate:

Days.daysBetween(new LocalDate(start), new LocalDate(end)).getDays() 

令人恼火的是，withTimeAtStartOfDay答案是错误的，但只是偶尔错误。你想要的:

Days.daysBetween(start.toLocalDate(), end.toLocalDate()).getDays()

事实证明，“午夜/一天的开始”有时意味着凌晨1点(夏令时在某些地方是这样发生的)。daysBetween不能正确处理。

// 5am on the 20th to 1pm on the 21st, October 2013, Brazil
DateTimeZone BRAZIL = DateTimeZone.forID("America/Sao_Paulo");
DateTime start = new DateTime(2013, 10, 20, 5, 0, 0, BRAZIL);
DateTime end = new DateTime(2013, 10, 21, 13, 0, 0, BRAZIL);
System.out.println(daysBetween(start.withTimeAtStartOfDay(),
                               end.withTimeAtStartOfDay()).getDays());
// prints 0
System.out.println(daysBetween(start.toLocalDate(),
                               end.toLocalDate()).getDays());
// prints 1

通过LocalDate可以避免整个问题。

天类

使用withTimeAtStartOfDay方法使用Days类应该可以工作:

Days.daysBetween(start.withTimeAtStartOfDay() , end.withTimeAtStartOfDay() ).getDays() 

public static int getDifferenceIndays(long timestamp1, long timestamp2) {
    final int SECONDS = 60;
    final int MINUTES = 60;
    final int HOURS = 24;
    final int MILLIES = 1000;
    long temp;
    if (timestamp1 < timestamp2) {
        temp = timestamp1;
        timestamp1 = timestamp2;
        timestamp2 = temp;
    }
    Calendar startDate = Calendar.getInstance(TimeZone.getDefault());
    Calendar endDate = Calendar.getInstance(TimeZone.getDefault());
    endDate.setTimeInMillis(timestamp1);
    startDate.setTimeInMillis(timestamp2);
    if ((timestamp1 - timestamp2) < 1 * HOURS * MINUTES * SECONDS * MILLIES) {
        int day1 = endDate.get(Calendar.DAY_OF_MONTH);
        int day2 = startDate.get(Calendar.DAY_OF_MONTH);
        if (day1 == day2) {
            return 0;
        } else {
            return 1;
        }
    }
    int diffDays = 0;
    startDate.add(Calendar.DAY_OF_MONTH, diffDays);
    while (startDate.before(endDate)) {
        startDate.add(Calendar.DAY_OF_MONTH, 1);
        diffDays++;
    }
    return diffDays;
}

你可以使用LocalDate:

Days.daysBetween(new LocalDate(start), new LocalDate(end)).getDays() 

接受的答案构建了两个LocalDate对象，如果要读取大量数据，这是非常昂贵的。 我用这个:

  public static int getDaysBetween(DateTime earlier, DateTime later)
  {
    return (int) TimeUnit.MILLISECONDS.toDays(later.getMillis()- earlier.getMillis());
  }

通过调用getMillis()，您可以使用已经存在的变量。 然后，使用简单的算术计算，不创建任何对象。