我有一些东西在设置。py，我想能够从模板访问，但我不知道如何做到这一点。我已经试过了
{{CONSTANT_NAME}}
但这似乎并不奏效。这可能吗?
当前回答
将这段代码添加到名为context_processors.py的文件中:
from django.conf import settings as django_settings
def settings(request):
return {
'settings': django_settings,
}
然后，在你的设置文件中，包括一个路径，如'speed .core.base.context_processors。在TEMPLATES中的context_processors设置中的settings'(包含你的应用程序名称和路径)。
(例如，你可以看到settings/base.py和context_processors.py)。
然后可以在任何模板代码中使用特定的设置。例如:
{% if settings.SITE_ID == settings.SPEEDY_MATCH_SITE_ID %}
更新:上面的代码向模板公开了所有设置，包括敏感信息，如SECRET_KEY。黑客可能滥用此特性在模板中显示此类信息。如果你只想将特定的设置暴露给模板，请使用下面的代码:
def settings(request):
settings_in_templates = {}
for attr in ["SITE_ID", ...]: # Write here the settings you want to expose to the templates.
if (hasattr(django_settings, attr)):
settings_in_templates[attr] = getattr(django_settings, attr)
return {
'settings': settings_in_templates,
}
其他回答
将这段代码添加到名为context_processors.py的文件中:
from django.conf import settings as django_settings
def settings(request):
return {
'settings': django_settings,
}
然后，在你的设置文件中，包括一个路径，如'speed .core.base.context_processors。在TEMPLATES中的context_processors设置中的settings'(包含你的应用程序名称和路径)。
(例如，你可以看到settings/base.py和context_processors.py)。
然后可以在任何模板代码中使用特定的设置。例如:
{% if settings.SITE_ID == settings.SPEEDY_MATCH_SITE_ID %}
更新:上面的代码向模板公开了所有设置，包括敏感信息，如SECRET_KEY。黑客可能滥用此特性在模板中显示此类信息。如果你只想将特定的设置暴露给模板，请使用下面的代码:
def settings(request):
settings_in_templates = {}
for attr in ["SITE_ID", ...]: # Write here the settings you want to expose to the templates.
if (hasattr(django_settings, attr)):
settings_in_templates[attr] = getattr(django_settings, attr)
return {
'settings': settings_in_templates,
}
我稍微改进了chrisdew的答案(创建自己的标签)。
首先，创建文件yourapp/templatetags/value_from_settings.py，在其中定义你自己的新标签value_from_settings:
from django.template import TemplateSyntaxError, Variable, Node, Variable, Library
from yourapp import settings
register = Library()
# I found some tricks in URLNode and url from defaulttags.py:
# https://code.djangoproject.com/browser/django/trunk/django/template/defaulttags.py
@register.tag
def value_from_settings(parser, token):
bits = token.split_contents()
if len(bits) < 2:
raise TemplateSyntaxError("'%s' takes at least one " \
"argument (settings constant to retrieve)" % bits[0])
settingsvar = bits[1]
settingsvar = settingsvar[1:-1] if settingsvar[0] == '"' else settingsvar
asvar = None
bits = bits[2:]
if len(bits) >= 2 and bits[-2] == 'as':
asvar = bits[-1]
bits = bits[:-2]
if len(bits):
raise TemplateSyntaxError("'value_from_settings' didn't recognise " \
"the arguments '%s'" % ", ".join(bits))
return ValueFromSettings(settingsvar, asvar)
class ValueFromSettings(Node):
def __init__(self, settingsvar, asvar):
self.arg = Variable(settingsvar)
self.asvar = asvar
def render(self, context):
ret_val = getattr(settings,str(self.arg))
if self.asvar:
context[self.asvar] = ret_val
return ''
else:
return ret_val
你可以通过以下方式在模板中使用这个标签:
{% load value_from_settings %}
[...]
{% value_from_settings "FQDN" %}
或通过
{% load value_from_settings %}
[...]
{% value_from_settings "FQDN" as my_fqdn %}
as的优点是…这使得它很容易通过一个简单的{{my_fqdn}}在blocktrans块中使用。
一个更完整的实现。
/项目/ settings.py
APP_NAME = 'APP'
- app - templatetags settings_value . py
from django import template
from django.conf import settings
register = template.Library()
@register.simple_tag
def settings_value(name):
return getattr(settings, name, "")
/app/templates/index.html
<!DOCTYPE html>
{% load static %}
{% load settings_value %}
<head>
<title>{% settings_value "APP_NAME" %}</title>
...
我喜欢Berislav的解决方案，因为在简单的网站上，它干净有效。我不喜欢的是随意地暴露所有的设置常数。所以我最后是这样做的:
from django import template
from django.conf import settings
register = template.Library()
ALLOWABLE_VALUES = ("CONSTANT_NAME_1", "CONSTANT_NAME_2",)
# settings value
@register.simple_tag
def settings_value(name):
if name in ALLOWABLE_VALUES:
return getattr(settings, name, '')
return ''
用法:
{% settings_value "CONSTANT_NAME_1" %}
This protects any constants that you have not named from use in the template, and if you wanted to get really fancy, you could set a tuple in the settings, and create more than one template tag for different pages, apps or areas, and simply combine a local tuple with the settings tuple as needed, then do the list comprehension to see if the value is acceptable. I agree, on a complex site, this is a bit simplistic, but there are values that would be nice to have universally in templates, and this seems to work nicely. Thanks to Berislav for the original idea!
如果你希望每个请求和模板都有一个值，那么使用上下文处理器更合适。
方法如下:
Make a context_processors.py file in your app directory. Let's say I want to have the ADMIN_PREFIX_VALUE value in every context: from django.conf import settings # import the settings file def admin_media(request): # return the value you want as a dictionnary. you may add multiple values in there. return {'ADMIN_MEDIA_URL': settings.ADMIN_MEDIA_PREFIX} add your context processor to your settings.py file: TEMPLATES = [{ # whatever comes before 'OPTIONS': { 'context_processors': [ # whatever comes before "your_app.context_processors.admin_media", ], } }] Use RequestContext in your view to add your context processors in your template. The render shortcut does this automatically: from django.shortcuts import render def my_view(request): return render(request, "index.html") and finally, in your template: ... <a href="{{ ADMIN_MEDIA_URL }}">path to admin media</a> ...
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