如何删除已合并的分支?我可以一次删除所有分支,而不是逐个删除每个分支吗?


当前回答

截至2018.07

将其添加到~/.gitconfig的[alias]部分:

sweep = !"f() { git branch --merged | egrep -v \"(^\\*|master|dev)\" || true | xargs git branch -d; }; f"

现在,您只需调用git扫描来执行所需的清理。

其他回答

您需要从这些命令中排除master、main和develop分支。

本地git清除:

git branch --merged | grep -v '\*\|master\|main\|develop' | xargs -n 1 git branch -d

远程清零:

git branch -r --merged | grep -v '\*\|master\|main\|develop' | sed 's/origin\///' | xargs -n 1 git push --delete origin

同步远程分支的本地注册表:

git fetch -p

如果您使用的是Windows,您可以使用Windows Powershell或Powershell 7以及Out GridView来创建一个漂亮的分支列表,并用鼠标选择要删除的分支:

git branch --format "%(refname:short)" --merged  | Out-GridView -PassThru | % { git branch -d $_ }

单击“确定”后,Powershell会将这些分支名称传递给gitbranch-d命令并删除它们

要删除已合并到主分支的本地分支,我使用以下别名(git-config-e--global):

cleanup = "!git branch --merged master | grep -v '^*\\|master' | xargs -n 1 git branch -D"

我使用gitbranch-D来避免错误:分支“somebranch”未完全合并。消息,而我的当前签出与主分支不同。

我的Bash脚本贡献大致基于mmrobin的答案。

它需要一些有用的参数来指定include和exclude,或者只检查/删除本地或远程分支,而不是两者。

#!/bin/bash

# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1

while [ $# -gt 0 ]; do
  case "$1" in
  -i) shift; includes="$includes $1" ;;
  -e) shift; excludes="$1" ;;
  --no-local) local=0 ;;
  --no-remote) remote=0 ;;
  --all) merged= ;;
  *) echo "Unknown argument $1"; exit 1 ;;
  esac
  shift   # next option
done

if [ "$includes" == "" ]; then
  includes=".*"
else
  includes="($(echo $includes | sed -e 's/ /|/g'))"
fi

current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
  echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"

git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
  echo "No existing branches have been merged into $current_branch."
else
  echo "This will remove the following branches:"
  if [ "$remote" == 1 -a -n "$remote_branches" ]; then
    echo "$remote_branches"
  fi
  if [ "$local" == 1 -a -n "$local_branches" ]; then
    echo "$local_branches"
  fi
  read -p "Continue? (y/n): " -n 1 choice
  echo
  if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
    if [ "$remote" == 1 ]; then
      remotes=$(git remote)
      # Remove remote branches
      for remote in $remotes
      do
        branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
        git push $remote $branches
      done
    fi

    if [ "$local" == 1 ]; then
      # Remove local branches
      locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
      if [ -z "$locals" ]; then
        echo "No branches removed."
      else
        git branch -d $(echo "$locals" | tr -d '\n')
      fi
    fi
  fi
fi

如果您想删除已合并到当前所在分支的所有本地分支,那么我根据前面的回答提出了一个安全的命令:

git branch --merged | grep -v \* | grep -v '^\s*master$' | xargs -t -n 1 git branch -d

此命令不会影响当前分支或主分支。它还将使用xargs的-t标志告诉您它在做什么。