谁使用 @pvl 解决方案,并希望它通过 ESLint Prefer 模板,那么这里是一个版本,我使用模板字母而不是字符集合。

validateEmail(email) {
    let sQtext = '[^\\x0d\\x22\\x5c\\x80-\\xff]';
    let sDtext = '[^\\x0d\\x5b-\\x5d\\x80-\\xff]';
    let sAtom = '[^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+';
    let sQuotedPair = '\\x5c[\\x00-\\x7f]';
    let sDomainLiteral = `\\x5b(${sDtext}|${sQuotedPair})*\\x5d`;
    let sQuotedString = `\\x22(${sQtext}|${sQuotedPair})*\\x22`;
    let sDomainRef = sAtom;
    let sSubDomain = `(${sDomainRef}|${sDomainLiteral})`;
    let sWord = `(${sAtom}|${sQuotedString})`;
    let sDomain = `${sSubDomain}(\\x2e${sSubDomain})*`;
    let sLocalPart = `${sWord}(\\x2e${sWord})*`;
    let sAddrSpec = `${sLocalPart}\\x40${sDomain}`; // complete RFC822 email address spec
    let sValidEmail = `^${sAddrSpec}$`; // as whole string

    let reValidEmail = new RegExp(sValidEmail);

    return reValidEmail.test(email);
}

<pre>
**The personal_info part contains the following ASCII characters.
1.Uppercase (A-Z) and lowercase (a-z) English letters.
2.Digits (0-9).
3.Characters ! # $ % & ' * + - / = ? ^ _ ` { | } ~
4.Character . ( period, dot or fullstop) provided that it is not the first or last character and it will not come one after the other.**
</pre>
*Example of valid email id*
<pre>
yoursite@ourearth.com
my.ownsite@ourearth.org
mysite@you.me.net
xxxx@gmail.com
xxxxxx@yahoo.com
</pre>
<pre>
xxxx.ourearth.com [@ is not present] 
xxxx@.com.my [ tld (Top Level domain) can not start with dot "." ]
@you.me.net [ No character before @ ]
xxxx123@gmail.b [ ".b" is not a valid tld ]
xxxx@.org.org [ tld can not start with dot "." ]
.xxxx@mysite.org [ an email should not be start with "." ]
xxxxx()*@gmail.com [ here the regular expression only allows character, digit, underscore and dash ]
xxxx..1234@yahoo.com [double dots are not allowed
</pre>
**javascript mail code**

    function ValidateEmail(inputText)
    {
    var mailformat = /^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/;
    if(inputText.value.match(mailformat))
    {
    document.form1.text1.focus();
    return true;
    }
    else
    {
    alert("You have entered an invalid email address!");
    document.form1.text1.focus();
    return false;
    }
    }

\b[a-z][\w\d_\.]+@\w+\.[a-z]{2}[a-z]?\.?[a-z]{,2}\s

它允许:

abcxyz123@qwert.com    
abc123xyz@asdf.co.in   
abc1_xyz1@gmail1.com   
abc.xyz@gmail.com.in

这就是 node-validator 如何做到:

/^(?:[\w\!\#\$\%\&\'\*\+\-\/\=\?\^\`\{\|\}\~]+\.)*[\w\!\#\$\%\&\'\*\+\-\/\=\?\^\`\{\|\}\~]+@(?:(?:(?:[a-zA-Z0-9](?:[a-zA-Z0-9\-](?!\.)){0,61}[a-zA-Z0-9]?\.)+[a-zA-Z0-9](?:[a-zA-Z0-9\-](?!$)){0,61}[a-zA-Z0-9]?)|(?:\[(?:(?:[01]?\d{1,2}|2[0-4]\d|25[0-5])\.){3}(?:[01]?\d{1,2}|2[0-4]\d|25[0-5])\]))$/

我认为这是最好的解决方案:

/^[^\s@]+@[^\s@]+\.[^\s@]+$/

它允许以下格式:

1.  prettyandsimple@example.com
2.  very.common@example.com
3.  disposable.style.email.with+symbol@example.com
4.  other.email-with-dash@example.com
9.  #!$%&'*+-/=?^_`{}|~@example.org
6.  "()[]:,;@\\\"!#$%&'*+-/=?^_`{}| ~.a"@example.org
7.  " "@example.org (space between the quotes)
8.  üñîçøðé@example.com (Unicode characters in local part)
9.  üñîçøðé@üñîçøðé.com (Unicode characters in domain part)
10. Pelé@example.com (Latin)
11. δοκιμή@παράδειγμα.δοκιμή (Greek)
12. 我買@屋企.香港 (Chinese)
13. 甲斐@黒川.日本 (Japanese)
14. чебурашка@ящик-с-апельсинами.рф (Cyrillic)

它是显而易见的多元化,并允许所有重要的国际角色,同时仍然执行基本的 anything@anything.anything格式,它将阻止技术上允许的空间,但它们是如此罕见,我很高兴做到这一点。