export function stringFormat (str: string, ...args: string[]) {
     return args.reduce((acc, curr, i) => acc.replace(new RegExp("\\{" + i + "\\}", 'g'), curr), str);
}

+1 Zippo，但函数体需要如下所示，否则它会在每次迭代时附加当前字符串：

String.prototype.format = function() {
    var formatted = this;
    for (var arg in arguments) {
        formatted = formatted.replace("{" + arg + "}", arguments[arg]);
    }
    return formatted;
};

arg函数：

/**
 * Qt stil arg()
 * var scr = "<div id='%1' class='%2'></div>".arg("mydiv").arg("mydivClass");
 */
String.prototype.arg = function() {
    var signIndex = this.indexOf("%");
    var result = this;
    if (signIndex > -1 && arguments.length > 0) {
        var argNumber = this.charAt(signIndex + 1);
        var _arg = "%"+argNumber;
        var argCount = this.split(_arg);
        for (var itemIndex = 0; itemIndex < argCount.length; itemIndex++) {
            result = result.replace(_arg, arguments[0]);
        }
    }
    return result;
}

/**
 * Format string by replacing placeholders with value from element with
 * corresponsing index in `replacementArray`.
 * Replaces are made simultaneously, so that replacement values like
 * '{1}' will not mess up the function.
 *
 * Example 1:
 * ('{2} {1} {0}', ['three', 'two' ,'one']) -> 'one two three'
 *
 * Example 2:
 * ('{0}{1}', ['{1}', '{0}']) -> '{1}{0}'
 */
function stringFormat(formatString, replacementArray) {
    return formatString.replace(
        /\{(\d+)\}/g, // Matches placeholders, e.g. '{1}'
        function formatStringReplacer(match, placeholderIndex) {
            // Convert String to Number
            placeholderIndex = Number(placeholderIndex);

            // Make sure that index is within replacement array bounds
            if (placeholderIndex < 0 ||
                placeholderIndex > replacementArray.length - 1
            ) {
                return placeholderIndex;
            }

            // Replace placeholder with value from replacement array
            return replacementArray[placeholderIndex];
        }
    );
}

jsxt、Zippo

此选项更适合。

String.prototype.format = function() {
    var formatted = this;
    for (var i = 0; i < arguments.length; i++) {
        var regexp = new RegExp('\\{'+i+'\\}', 'gi');
        formatted = formatted.replace(regexp, arguments[i]);
    }
    return formatted;
};

使用此选项，我可以替换如下字符串：

'The {0} is dead. Don\'t code {0}. Code {1} that is open source!'.format('ASP', 'PHP');

使用您的代码，不会替换第二个｛0｝。；）

虽然不是世界上最推荐的功能，但它确实有效。

如果需要sprintf，只需复制并粘贴相同的函数，并将return console.log（sb）更改为只返回sb。

printf=函数（s，/*args…*/）{a=参数；al=a.length；如果（al<=1）返回-2；如果（al>=2&&s.toLowerCase（）.search（/%[a-z]/）==-1）返回-1；sb=s；对于（i=1；i<=al-1；i++）{sb=某人替换（/%[a-z]/，a[i]）；}返回控制台日志（sb）；}var someString=“您好%s\n现在是%s：%s%s。\n今天是%s\n”；printf（someString，“StackOverflowUser”，“5”，“48”，“PM”，“漂亮”）；