JavaScript中的sprintf（）函数模拟为Vue过滤器和String.protype.format（）扩展：

/**
 * Returns a formatted string.
 *
 * @param template
 * @param values
 * @return string
 */
String.format = function (template, ...values) {
    let i = -1;

    function callback(exp, p0, p1, p2, p3, p4) {
        if (exp === '%%') return '%';
        if (values[++i] === undefined) return undefined;

        exp = p2 ? parseInt(p2.substr(1)) : undefined;

        let base = p3 ? parseInt(p3.substr(1)) : undefined;
        let val;

        switch (p4) {
            case 's': val = values[i]; break;
            case 'c': val = values[i][0]; break;
            case 'f': val = parseFloat(values[i]).toFixed(exp); break;
            case 'p': val = parseFloat(values[i]).toPrecision(exp); break;
            case 'e': val = parseFloat(values[i]).toExponential(exp); break;
            case 'x': val = parseInt(values[i]).toString(base ? base : 16); break;
            case 'd': val = parseFloat(parseInt(values[i], base ? base : 10).toPrecision(exp)).toFixed(0); break;
        }
        val = typeof (val) == 'object' ? JSON.stringify(val) : val.toString(base);
        let sz = parseInt(p1); /* padding size */
        let ch = p1 && p1[0] === '0' ? '0' : ' '; /* isnull? */

        while (val.length < sz) val = p0 !== undefined ? val + ch : ch + val; /* isminus? */

        return val;
    }

    let regex = /%(-)?(0?[0-9]+)?([.][0-9]+)?([#][0-9]+)?([scfpexd%])/g;

    return template.replace(regex, callback);
}

String.prototype.format = function() {
    return String.format(this, ...arguments);
}

const StringFormat = {
    install: (Vue, options) => {
        Vue.filter('format', function () {
            return String.format(...arguments);
        });
    },
};

export default StringFormat;

原始答案：JavaScript相当于printf/String.Format

bobjs可以做到这一点：

var sFormat = "My name is {0} and I am {1} years old."; 
var result = bob.string.formatString(sFormat, "Bob", 29); 
console.log(result); 
//output: 
//========== 
// My name is Bob and I am 29 years old. 

+1 Zippo，但函数体需要如下所示，否则它会在每次迭代时附加当前字符串：

String.prototype.format = function() {
    var formatted = this;
    for (var arg in arguments) {
        formatted = formatted.replace("{" + arg + "}", arguments[arg]);
    }
    return formatted;
};

我们可以为Typescript使用一个简单的轻量级String.Format字符串操作库。

String.Format（）：

var id = image.GetId()
String.Format("image_{0}.jpg", id)
output: "image_2db5da20-1c5d-4f1a-8fd4-b41e34c8c5b5.jpg";

说明符的字符串格式：

var value = String.Format("{0:L}", "APPLE"); //output "apple"

value = String.Format("{0:U}", "apple"); // output "APPLE"

value = String.Format("{0:d}", "2017-01-23 00:00"); //output "23.01.2017"


value = String.Format("{0:s}", "21.03.2017 22:15:01") //output "2017-03-21T22:15:01"

value = String.Format("{0:n}", 1000000);
//output "1.000.000"

value = String.Format("{0:00}", 1);
//output "01"

对象的字符串格式，包括说明符：

var fruit = new Fruit();
fruit.type = "apple";
fruit.color = "RED";
fruit.shippingDate = new Date(2018, 1, 1);
fruit.amount = 10000;

String.Format("the {type:U} is {color:L} shipped on {shippingDate:s} with an amount of {amount:n}", fruit);
// output: the APPLE is red shipped on 2018-01-01 with an amount of 10.000

我将添加我自己的发现，这些发现是我问过之后发现的：

number_format（用于千位分隔符/货币格式）sprintf（作者同上）

遗憾的是，sprintf似乎不能像.NET的字符串格式那样处理千位分隔符格式。

用于jQuery.ajax（）成功函数。只传递一个参数，并用该对象的财产替换字符串作为{propertyName}：

String.prototype.format = function () {
    var formatted = this;
    for (var prop in arguments[0]) {
        var regexp = new RegExp('\\{' + prop + '\\}', 'gi');
        formatted = formatted.replace(regexp, arguments[0][prop]);
    }
    return formatted;
};

例子：

var userInfo = ("Email: {Email} - Phone: {Phone}").format({ Email: "someone@somewhere.com", Phone: "123-123-1234" });