你可以使用这个类:

import time 

import datetime

class TimingClass():

    def __init__(self):

        self.YEAR        = datetime.date.today().year
        self.MONTH       = datetime.date.today().month
        self.DATE        = datetime.date.today().day
        self.HOUR        = datetime.datetime.now().hour
        self.MINUTE      = datetime.datetime.now().minute
        self.SECONDS     = datetime.datetime.now().second
        
        self.TODAY       = datetime.date.today()
        self.YESTERDAY   = datetime.datetime.strftime( (self.TODAY - datetime.timedelta(days = 1)) , '%Y-%m-%d')
        self.TOMORROW   = datetime.datetime.strftime( (self.TODAY + datetime.timedelta(days = 1)) , '%Y-%m-%d')
        
        self.TODAY_datetime = datetime.datetime.combine(datetime.date.today(), datetime.datetime.min.time())

toisoformat/fromisoformat的替代方案:您可以使用date。Toordinal和datetime.fromordinal:

import datetime

start_date = datetime.date(1991, 2, 20)
start_date_midnight = datetime.datetime.fromordinal(start_date.toordinal())

我怀疑这比转换到/从字符串更有效。

你可以这样测试这个过程:

def test_datetime_from_date():
    for x in range(1,1000000):
        date_ = datetime.date.fromordinal(x)
        datetime_ = datetime.datetime.fromordinal(date_.toordinal())
        datetime_iso_date, t, datetime_iso_time = datetime_.isoformat().partition("T")
        assert datetime_iso_date == date_.isoformat()

你可以使用这个类:

import time 

import datetime

class TimingClass():

    def __init__(self):

        self.YEAR        = datetime.date.today().year
        self.MONTH       = datetime.date.today().month
        self.DATE        = datetime.date.today().day
        self.HOUR        = datetime.datetime.now().hour
        self.MINUTE      = datetime.datetime.now().minute
        self.SECONDS     = datetime.datetime.now().second
        
        self.TODAY       = datetime.date.today()
        self.YESTERDAY   = datetime.datetime.strftime( (self.TODAY - datetime.timedelta(days = 1)) , '%Y-%m-%d')
        self.TOMORROW   = datetime.datetime.strftime( (self.TODAY + datetime.timedelta(days = 1)) , '%Y-%m-%d')
        
        self.TODAY_datetime = datetime.datetime.combine(datetime.date.today(), datetime.datetime.min.time())

有几种方法，尽管我相信你提到的(和不喜欢的)是最易读的。

>>> import datetime
>>> t=datetime.date.today()
>>> datetime.datetime.fromordinal(t.toordinal())
datetime.datetime(2009, 12, 20, 0, 0)

>>> datetime.datetime(t.year, t.month, t.day)
datetime.datetime(2009, 12, 20, 0, 0)

>>> datetime.datetime(*t.timetuple()[:-4])
datetime.datetime(2009, 12, 20, 0, 0)

等等——但基本上它们都依赖于从date对象中适当地提取信息，并将其返回到datetime的适当的ctor或类函数中。

我是Python的新手。但是这段代码为我工作，它将我提供的指定输入转换为datetime。这是代码。如果我说错了，请指正。

import sys
from datetime import datetime
from time import mktime, strptime

user_date = '02/15/1989'
if user_date is not None:
     user_date = datetime.strptime(user_date,"%m/%d/%Y")
else:
     user_date = datetime.now()
print user_date

公认的答案是正确的，但我更倾向于避免使用datetime.min.time()，因为它的确切功能对我来说并不明显。如果这对你来说很明显，那你就更有力量。我对timetuple方法和对排序的依赖也有同样的感觉。

在我看来，在不依赖读者非常熟悉datetime模块API的情况下，最易读的、显式的方法是:

from datetime import date, datetime
today = date.today()
today_with_time = datetime(
    year=today.year, 
    month=today.month,
    day=today.day,
)

这就是我对“显性比隐性好”的看法。