或者用熊猫，

演示:

>>> d={'B':1,'A':2,'C':3}
>>> df=pd.DataFrame(d,index=[0]).sort_index(axis=1)
   A  B  C
0  2  1  3
>>> df.to_dict('int')[0]
{'A': 2, 'B': 1, 'C': 3}
>>> 

See:

这方面的文档 整只熊猫的记录

l = dict.keys()
l2 = l
l2.append(0)
l3 = []
for repeater in range(0, len(l)):
    smallnum = float("inf")
    for listitem in l2:
        if listitem < smallnum:
            smallnum = listitem
    l2.remove(smallnum)
    l3.append(smallnum)
l3.remove(0)
l = l3

for listitem in l:
    print(listitem)

在Python 3中。

>>> D1 = {2:3, 1:89, 4:5, 3:0}
>>> for key in sorted(D1):
    print (key, D1[key])

给了

1 89
2 3
3 0
4 5

找到了另一种方法:

import json
print json.dumps(d, sort_keys = True)

乌利希期刊指南: 1. 这也可以对嵌套对象进行排序(谢谢@DanielF)。 2. Python字典是无序的，因此只适用于打印或赋值给STR。

from operator import itemgetter
# if you would like to play with multiple dictionaries then here you go:
# Three dictionaries that are composed of first name and last name.
user = [
    {'fname': 'Mo', 'lname': 'Mahjoub'},
    {'fname': 'Abdo', 'lname': 'Al-hebashi'},
    {'fname': 'Ali', 'lname': 'Muhammad'}
]
#  This loop will sort by the first and the last names.
# notice that in a dictionary order doesn't matter. So it could put the first name first or the last name first. 
for k in sorted (user, key=itemgetter ('fname', 'lname')):
    print (k)

# This one will sort by the first name only.
for x in sorted (user, key=itemgetter ('fname')):
    print (x)

我发现对字典进行排序的一个简单方法是，根据要排序的字典的排序键:值项创建一个新字典。 如果你想对dict ={}排序，使用相关的方法检索它的所有项，使用sorted()函数对它们排序，然后创建新字典。

下面是使用字典理解的代码:

sorted_dict = {k:v for k,v in sorted(dict.items())}