当你在PHP和mysql中删除一些东西时，设置一个确认消息…

使用以下脚本代码:

<script>
    function Conform_Delete()
    {
       return conform("Are You Sure Want to Delete?");
    }
</script>

使用下面的HTML代码:

<a onclick="return Conform_Delete()" href="#">delete</a>

我用这种方法(laravel)-

<form id="delete-{{$category->id}}" action="{{route('category.destroy',$category->id)}}" style="display: none;" method="POST">
 @csrf
 @method('DELETE')
</form>

<a href="#" onclick="if (confirm('Are you sure want to delete this item?')) {
           event.preventDefault();
           document.getElementById('delete-{{$category->id}}').submit();
         }else{
           event.preventDefault();
         }">
  <i class="fa fa-trash"></i>
</a>

我知道这是老问题了，但我需要一个答案，这些答案都不是，但alpesh的答案对我有用，我想与可能有同样问题的人分享。

<script>    
function confirmDelete(url) {
    if (confirm("Are you sure you want to delete this?")) {
        window.open(url);
    } else {
        false;
    }       
}
</script>

普通版:

<input type="button" name="delete" value="Delete" onClick="confirmDelete('delete.php?id=123&title=Hello')">

我的PHP版本:

$deleteUrl = "delete.php?id=" .$id. "&title=" .$title;
echo "<input type=\"button\" name=\"delete\" value=\"Delete\" onClick=\"confirmDelete('" .$deleteUrl. "')\"/>";

这可能不是公开的正确方式，但在一个私人网站上，这对我来说是有效的。：）

<script>
function deleteItem()
{
   var resp = confirm("Do you want to delete this item???");
   if (resp == true) {
      //do something
   } 
   else {
      //do something
   }
}
</script>

使用onClick调用此函数

function ConfirmDelete()
{
  return confirm("Are you sure you want to delete?");
}


<input type="button" onclick="ConfirmDelete()">

function confirmDelete()
{
var r=confirm("Are you sure you want to delte this image");
if (r==true)
{
//User Pressed okay. Delete

}
else
{
//user pressed cancel. Do nothing
    }
 }
<img src="deleteicon.png" onclick="confirmDelete()">

您可能希望使用confirmDelete传递一些数据，以确定要删除哪个条目