我试图在网页上的特定“输入”标签中提取单个“值”属性的内容。我使用以下代码:
import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()
from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)
inputTag = soup.findAll(attrs={"name" : "stainfo"})
output = inputTag['value']
print str(output)
我得到TypeError:列表索引必须是整数，而不是str
尽管如此，从Beautifulsoup文档中，我了解到字符串在这里不应该是一个问题……但我不是专家，我可能误解了。
任何建议都非常感谢!
当前回答
你可以尝试使用名为requests_html的强大的新包:
from requests_html import HTMLSession
session = HTMLSession()
r = session.get("https://www.bbc.co.uk/news/technology-54448223")
date = r.html.find('time', first = True) # finding a "tag" called "time"
print(date) # you will have: <Element 'time' datetime='2020-10-07T11:41:22.000Z'>
# To get the text inside the "datetime" attribute use:
print(date.attrs['datetime']) # you will get '2020-10-07T11:41:22.000Z'
其他回答
你可以尝试使用名为requests_html的强大的新包:
from requests_html import HTMLSession
session = HTMLSession()
r = session.get("https://www.bbc.co.uk/news/technology-54448223")
date = r.html.find('time', first = True) # finding a "tag" called "time"
print(date) # you will have: <Element 'time' datetime='2020-10-07T11:41:22.000Z'>
# To get the text inside the "datetime" attribute use:
print(date.attrs['datetime']) # you will get '2020-10-07T11:41:22.000Z'
.find_all()返回所有找到元素的列表，因此:
input_tag = soup.find_all(attrs={"name" : "stainfo"})
Input_tag是一个列表(可能只包含一个元素)。根据你想要什么，你应该做:
output = input_tag[0]['value']
或者使用.find()方法，只返回一个(第一个)找到的元素:
input_tag = soup.find(attrs={"name": "stainfo"})
output = input_tag['value']
我实际上会建议你一种节省时间的方法，假设你知道什么样的标签有这些属性。
假设标签xyz的属性管名为“staininfo”..
full_tag = soup.findAll("xyz")
我想让你明白full_tag是一个列表
for each_tag in full_tag:
staininfo_attrb_value = each_tag["staininfo"]
print staininfo_attrb_value
因此，您可以获得所有标记xyz的staininfo的所有attrb值
如果你想从上面的源代码中检索多个属性值，你可以使用findAll和一个列表推导式来获得你需要的一切:
import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()
from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)
inputTags = soup.findAll(attrs={"name" : "stainfo"})
### You may be able to do findAll("input", attrs={"name" : "stainfo"})
output = [x["stainfo"] for x in inputTags]
print output
### This will print a list of the values.
在Python 3中。X，简单地使用get(attr_name)在你的标签对象，你得到使用find_all:
xmlData = None
with open('conf//test1.xml', 'r') as xmlFile:
xmlData = xmlFile.read()
xmlDecoded = xmlData
xmlSoup = BeautifulSoup(xmlData, 'html.parser')
repElemList = xmlSoup.find_all('repeatingelement')
for repElem in repElemList:
print("Processing repElem...")
repElemID = repElem.get('id')
repElemName = repElem.get('name')
print("Attribute id = %s" % repElemID)
print("Attribute name = %s" % repElemName)
XML文件conf//test1.xml，如下所示:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
<singleElement>
<subElementX>XYZ</subElementX>
</singleElement>
<repeatingElement id="11" name="Joe"/>
<repeatingElement id="12" name="Mary"/>
</root>
打印:
Processing repElem...
Attribute id = 11
Attribute name = Joe
Processing repElem...
Attribute id = 12
Attribute name = Mary
