为什么他们决定在Java和。net(和其他一些语言)中使字符串不可变?为什么不让它变呢?
当前回答
这主要是出于安全考虑。如果您不能相信您的字符串是防篡改的,那么保护系统就困难得多。
其他回答
根据Effective Java,第4章,第73页,第二版:
"There are many good reasons for this: Immutable classes are easier to design, implement, and use than mutable classes. They are less prone to error and are more secure. [...] "Immutable objects are simple. An immutable object can be in exactly one state, the state in which it was created. If you make sure that all constructors establish class invariants, then it is guaranteed that these invariants will remain true for all time, with no effort on your part. [...] Immutable objects are inherently thread-safe; they require no synchronization. They cannot be corrupted by multiple threads accessing them concurrently. This is far and away the easiest approach to achieving thread safety. In fact, no thread can ever observe any effect of another thread on an immutable object. Therefore, immutable objects can be shared freely [...]
同一章的其他要点:
不仅可以共享不可变对象,还可以共享它们的内部结构。 […] 不可变对象为其他对象提供了很好的构建块,无论是可变的还是不可变的。 […] 不可变类的唯一缺点是,它们需要为每个不同的值提供一个单独的对象。
实际上,字符串在java中是不可变的原因与安全性没有太大关系。主要有以下两个原因:
Thead安全:
字符串是被广泛使用的对象类型。因此,它或多或少可以保证在多线程环境中使用。字符串是不可变的,以确保在线程之间共享字符串是安全的。拥有一个不可变的字符串可以确保当线程A将字符串传递给另一个线程B时,线程B不能意外地修改线程A的字符串。
Not only does this help simplify the already pretty complicated task of multi-threaded programming, but it also helps with performance of multi-threaded applications. Access to mutable objects must somehow be synchronized when they can be accessed from multiple threads, to make sure that one thread doesn't attempt to read the value of your object while it is being modified by another thread. Proper synchronization is both hard to do correctly for the programmer, and expensive at runtime. Immutable objects cannot be modified and therefore do not need synchronization.
性能:
虽然已经提到了字符串实习,但它只代表了Java程序内存效率的一小部分提高。只有字符串字面量被存储。这意味着只有源代码中相同的字符串才会共享相同的字符串对象。如果你的程序动态地创建了相同的字符串,它们将在不同的对象中表示。
More importantly, immutable strings allow them to share their internal data. For many string operations, this means that the underlying array of characters does not need to be copied. For example, say you want to take the five first characters of String. In Java, you would calls myString.substring(0,5). In this case, what the substring() method does is simply to create a new String object that shares myString's underlying char[] but who knows that it starts at index 0 and ends at index 5 of that char[]. To put this in graphical form, you would end up with the following:
| myString |
v v
"The quick brown fox jumps over the lazy dog" <-- shared char[]
^ ^
| | myString.substring(0,5)
这使得这种操作非常便宜,O(1),因为该操作既不依赖于原始字符串的长度,也不依赖于我们需要提取的子字符串的长度。这种行为也有一些内存好处,因为许多字符串可以共享它们的底层char[]。
至少有两个原因。
第一-安全http://www.javafaq.nu/java-article1060.html
The main reason why String made immutable was security. Look at this example: We have a file open method with login check. We pass a String to this method to process authentication which is necessary before the call will be passed to OS. If String was mutable it was possible somehow to modify its content after the authentication check before OS gets request from program then it is possible to request any file. So if you have a right to open text file in user directory but then on the fly when somehow you manage to change the file name you can request to open "passwd" file or any other. Then a file can be modified and it will be possible to login directly to OS.
第二-内存效率http://hikrish.blogspot.com/2006/07/why-string-class-is-immutable.html
JVM internally maintains the "String Pool". To achive the memory efficiency, JVM will refer the String object from pool. It will not create the new String objects. So, whenever you create a new string literal, JVM will check in the pool whether it already exists or not. If already present in the pool, just give the reference to the same object or create the new object in the pool. There will be many references point to the same String objects, if someone changes the value, it will affect all the references. So, sun decided to make it immutable.
这是一种权衡。字符串进入String池,当您创建多个相同的字符串时,它们共享相同的内存。设计人员认为这种节省内存的技术在一般情况下会很好地工作,因为程序倾向于反复处理相同的字符串。
缺点是连接产生了许多额外的字符串,这些字符串只是过渡性的,只是垃圾,实际上会损害内存性能。在这些情况下,可以使用StringBuffer和StringBuilder(在Java中,。net中也有StringBuilder)来保存内存。
Java中的字符串并不是真正不可变的,您可以使用反射和或类加载来更改它们的值。你不应该依赖这个属性来保证安全。 有关示例请参见:Java中的魔术
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