只是想知道,是否有一种方法可以向.includes方法添加多个条件,例如:

    var value = str.includes("hello", "hi", "howdy");

想象一下逗号表示“或”。

它现在询问字符串是否包含hello, hi或howdy。所以只有当其中一个条件为真。

有什么方法可以做到吗?


当前回答

const givenArray = ['Hi, how are you', 'how are you', 'howdy, how you doing'] const includeValues = ["hello", "hi", "howdy"] const filteredStrArray = givenArray。filter(str => includeValues)str.toLowerCase().includes(value))) console.log (filteredStrArray);

其他回答

你可以这样做

["hello", "hi", "howdy"].includes(str)

即使有且只有一个条件为真,它也能工作:

var str = "bonjour le monde vive le javascript";
var arr = ['bonjour','europe', 'c++'];

function contains(target, pattern){
    var value = 0;
    pattern.forEach(function(word){
      value = value + target.includes(word);
    });
    return (value === 1)
}

console.log(contains(str, arr));

与数组数据/的精确匹配

const dataArray = ["amoos", "rifat", "hello"]; const findId = (data, id) => { 让res = data。Find (el => el == id) 返回res ?真:假; } console.log(findId(dataArray, 'Hi')) // false console.log(findId(dataArray, 'amoos')) // true

也许晚了,但这里是我的解决方案为一个数组和两个或更多的项目 / 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' '))

console.log(/ 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' ')))

您可以使用这里引用的.some方法。

some()方法测试数组中是否至少有一个元素 通过由提供的函数实现的测试。

// test cases const str1 = 'hi hello, how do you do?'; const str2 = 'regular string'; const str3 = 'hello there'; // do the test strings contain these terms? const conditions = ["hello", "hi", "howdy"]; // run the tests against every element in the array const test1 = conditions.some(el => str1.includes(el)); const test2 = conditions.some(el => str2.includes(el)); // strictly check that contains 1 and only one match const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1; // display results console.log(`Loose matching, 2 matches "${str1}" => ${test1}`); console.log(`Loose matching, 0 matches "${str2}" => ${test2}`); console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);

另外,正如下面一位用户提到的那样,匹配上面提到的“恰好一个”外观也很有趣(这是OP要求的)。这可以类似地用.reduce计算交点,然后检查它们是否等于1。