只是想知道,是否有一种方法可以向.includes方法添加多个条件,例如:

    var value = str.includes("hello", "hi", "howdy");

想象一下逗号表示“或”。

它现在询问字符串是否包含hello, hi或howdy。所以只有当其中一个条件为真。

有什么方法可以做到吗?


当前回答

也许晚了,但这里是我的解决方案为一个数组和两个或更多的项目 / 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' '))

console.log(/ 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' ')))

其他回答

这可以通过使用Array和RegEx的一些/每个方法来完成。

检查list(array)中的所有单词是否存在于字符串中:

const multiSearchAnd = (text, searchWords) => (
  searchWords.every((el) => {
    return text.match(new RegExp(el,"i"))
  })
)

multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["cle", "hire"]) //returns false
multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true

检查list(array)中的任何单词是否存在于字符串中:

const multiSearchOr = (text, searchWords) => (
  searchWords.some((el) => {
    return text.match(new RegExp(el,"i"))
  })
)

multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "zzzz"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "1111"]) //returns false

这是一个有争议的选择:

String.prototype.includesOneOf = function(arrayOfStrings) {
  if(!Array.isArray(arrayOfStrings)) {
    throw new Error('includesOneOf only accepts an array')
  }
  return arrayOfStrings.some(str => this.includes(str))
}

允许你做以下事情:

'Hi, hope you like this option'.toLowerCase().includesOneOf(["hello", "hi", "howdy"]) // True

const givenArray = ['Hi, how are you', 'how are you', 'howdy, how you doing'] const includeValues = ["hello", "hi", "howdy"] const filteredStrArray = givenArray。filter(str => includeValues)str.toLowerCase().includes(value))) console.log (filteredStrArray);

也许晚了,但这里是我的解决方案为一个数组和两个或更多的项目 / 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' '))

console.log(/ 1 | 2 /。Test (['one', 'two', 'three', 'four']。加入(' ')))

另一个!

let result const givenStr = 'A, X' //values separated by comma or space. const allowed = ['A', 'B'] const given = givenStr.split(/[\s,]+/).filter(v => v) console.log('given (array):', given) // given contains none or only allowed values: result = given.reduce((acc, val) => { return acc && allowed.includes(val) }, true) console.log('given contains none or only allowed values:', result) // given contains at least one allowed value: result = given.reduce((acc, val) => { return acc || allowed.includes(val) }, false) console.log('given contains at least one allowed value:', result)