如何在SQL中从DateTime格式获取时间?

我想从DateTime列使用SQL查询只得到时间使用SQL Server 2005和2008 默认的输出:

AttDate                   
==
2011-02-09 13:09:00    
2011-02-09 14:10:00

我想要这样的输出:

AttDate                Time 
==
2011-02-09 13:09:00    13:09
2011-02-09 14:10:00    14:10

当前回答

Declare @date Datetime = '06/18/2021 14:24:31';
Select FORMAT(@date, 'h\:m tt', 'en-US') As Timey

输出:

2:24pm

其他回答

试试这个

时间日期 Select cast(getdate() as time(0)) 时间到TinyTime 选择强制转换(orig_time作为时间(0))

MSSQL2012或以上版本

cast(dateadd(ms,datediff(ms, [StartDateTime], [StopDateTime]),0) as Time(0))

…或…

convert(time(0),dateadd(ms,datediff(ms, [StartDateTime], [StopDateTime]),0) )

Declare @date Datetime = '06/18/2021 14:24:31';
Select FORMAT(@date, 'h\:m tt', 'en-US') As Timey

输出:

2:24pm

SQL Server 2008:

SELECT cast(AttDate as time) [time]
FROM yourtable

早期版本:

SELECT convert(char(5), AttDate, 108) [time]
FROM yourtable

select convert(char(5), tbl_CustomerBooking.CheckInTime, 108) AS [time]
from tbl_CustomerBooking

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