我觉得这就是你要找的…

def action1(action):
    print(f'doing {action} here!')

def perform(function):
    return function()

perform(lambda : action1('business action'))  

Lambda将func和args打包在闭包中并传递给perform()

感谢大卫·比斯利。

你可以像这样使用functools中的partial函数。

from functools import partial

def perform(f):
    f()

perform(Action1)
perform(partial(Action2, p))
perform(partial(Action3, p, r))

也适用于关键字

perform(partial(Action4, param1=p))

尽管所有的回答都非常准确，解释得很好。 我想澄清一下，你也可以传递匿名函数。

def perform(fun, *arg):
    return fun(*arg)

# Pass anonymous function
print(perform(lambda x: x + 1, 3)) # output: 4
print(perform(lambda x, y: x + y + 1, 3, 2)) # output: 6

# Pass defined function
perform(lambda: action1())
perform(lambda: action2(p))
perform(lambda: action3(p, r))

你是这个意思吗?

def perform(fun, *args):
    fun(*args)

def action1(args):
    # something

def action2(args):
    # something

perform(action1)
perform(action2, p)
perform(action3, p, r)

这就是lambda的含义:

def perform(f):
    f()

perform(lambda: action1())
perform(lambda: action2(p))
perform(lambda: action3(p, r))

我觉得这就是你要找的…

def action1(action):
    print(f'doing {action} here!')

def perform(function):
    return function()

perform(lambda : action1('business action'))  

Lambda将func和args打包在闭包中并传递给perform()

感谢大卫·比斯利。