在es6模板文字，如何包装一个长模板文字到多行而不创建一个新的行在字符串?
例如，如果你这样做:
const text = `a very long string that just continues
and continues and continues`
然后它将为字符串创建一个新的行符号，就像解释它有一个新的行一样。如何在不创建换行符的情况下将长模板文字包装到多行?
当前回答
如果你在字面值的换行符处引入了一个续行符(\)，它不会在输出时创建换行符:
const text = `a very long string that just continues\
and continues and continues`;
console.log(text); // a very long string that just continuesand continues and continues
其他回答
如果你在字面值的换行符处引入了一个续行符(\)，它不会在输出时创建换行符:
const text = `a very long string that just continues\
and continues and continues`;
console.log(text); // a very long string that just continuesand continues and continues
另一种选择是使用Array。像这样加入:
[
'This is a very long string. ',
'It just keeps going ',
'and going ',
'and going ',
'and going ',
'and going ',
'and going ',
'and going',
].join('')
类似于Doug的回答，这被我的TSLint配置所接受，并且不受我的IntelliJ自动格式化器的影响:
const text = `a very long string that just ${
continues
} and ${continues} and ${continues}`
这是一个旧的。但它出现了。如果你在编辑器中留下任何空格，它会把它们放在那里。
if
const text = `a very long string that just continues\
and continues and continues`;
只要用普通的+符号
if
const text = `a very long string that just continues` +
`and continues and continues`;
你可以直接吃掉模板文字中的换行符。
//感谢https://twitter.com/awbjs给我介绍这个想法 //这里:https://esdiscuss.org/topic/multiline-template-strings-that-don-t-break-indentation const printLongLine = continue => { Const text = '一个很长的字符串，只有${continues}${" }和${continuations}和${continuations} '; 返回文本; ｝ console.log (printLongLine('继续'));
