我的问题是:不使用powershell命令可以获得azure活动目录租户id吗?
我找到了这两个博客，有了这个帮助，我已经能够从powershell获得租户ID和订阅ID。这是找回房客的唯一方法吗?
在Windows PowerShell中获取Windows Azure活动目录租户ID
Windows Azure AD认证支持PowerShell
谢谢
当前回答
从Java:
public static String GetSubscriptionTenantId (String subscriptionId) throws ClientProtocolException, IOException
{
String tenantId = null;
String url = "https://management.azure.com/subscriptions/" + subscriptionId + "?api-version=2016-01-01";
HttpClient client = HttpClientBuilder.create().build();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
Header[] headers = response.getAllHeaders();
for (Header header : headers)
{
if (header.getName().equals("WWW-Authenticate"))
{
// split by '"' to get the URL, split the URL by '/' to get the ID
tenantId = header.getValue().split("\"")[1].split("/")[3];
}
}
return tenantId;
}
其他回答
我的团队真的厌倦了为我们的O365和Azure项目寻找租户ID。开发人员、支持团队、销售团队，每个人都在某个时候需要它，但从来不记得该怎么做。
所以我们建立了这个小网站，与whatismyip.com相同。希望对你有用!
如何找到我的Microsoft 365、Azure或SharePoint在线租户ID?
您可以运行一个简单的curl调用来获得azure订阅的租户id，而无需任何身份验证。
做一个卷曲调用:
https://management.azure.com/subscriptions/{订阅id} ? api版本= 2015-01-01
请求失败，但您将能够从响应报头中获得租户id。租户id出现在一行中，后面跟着“WWW-Authenticate: holder authorization_uri="https://login.windows.net/"
您可以使用curl -v来显示响应头。
为我工作的是这个(az登录后):
az account show |grep tenantId | awk {'print $2'} |tr -d '[:punct:]'
通过PowerShell匿名:
(Invoke-WebRequest https://login.windows.net/YOURDIRECTORYNAME.onmicrosoft.com/.well-known/openid-configuration|ConvertFrom-Json).token_endpoint.Split('/')[3]
For AAD-B2C it is fairly simple. From Azure Portal with a B2C directory associated, go to your B2C directory (I added the "Azure AD B2C" to my portal's left menu). In the B2C directory click on "User flows (policies) directory menu item. In the policies pane click on one of your policies you previously added to select it. It should open a pane for the policy. Click "Properties". In the next pane is a section, "Token compatibility settings" which has a property "Issuer". Your AAD-B2C tenant GUID is contained in the URL.
