你可以这样使用rabbitmqctl eval:

rabbitmqctl eval 'IfUnused = false, IfEmpty = true, MatchRegex = 
<<"^prefix-">>, [rabbit_amqqueue:delete(Q, IfUnused, IfEmpty) || Q <- 
rabbit_amqqueue:list(), re:run(element(4, element(2, Q)), MatchRegex) 
=/= nomatch ].' 

上述操作将删除所有有名称的vhosts中的所有空队列 以“前缀-”开头。 你可以编辑变量IfUnused, IfEmpty， 和MatchRegex根据您的要求。

试试这个:

rabbitmqctl list_queues -q name > q.txt
IFS=$'\n' read -d '' -r -a queues < q.txt
count=${#queues[@]}
i=1; while (($i < $count)); do echo ${queues[$i]};rabbitmqctl delete_queue ${queues[$i]};i=$((i+1)); done

Okay, important qualifier for this answer: The question does ask to use either rabbitmqctl OR rabbitmqadmin to solve this, my answer needed to use both. Also, note that this was tested on MacOS 10.12.6 and the versions of the rabbitmqctl and rabbitmqadmin that are installed when installing rabbitmq with Homebrew and which is identified with brew list --versions as rabbitmq 3.7.0 rabbitmqctl list_queues -p <VIRTUAL_HOSTNAME> name | sed 1,2d | xargs -I qname rabbitmqadmin --vhost <VIRTUAL_HOSTNAME> delete queue name=qname

你可以这样使用rabbitmqctl eval:

rabbitmqctl eval 'IfUnused = false, IfEmpty = true, MatchRegex = 
<<"^prefix-">>, [rabbit_amqqueue:delete(Q, IfUnused, IfEmpty) || Q <- 
rabbit_amqqueue:list(), re:run(element(4, element(2, Q)), MatchRegex) 
=/= nomatch ].' 

上述操作将删除所有有名称的vhosts中的所有空队列 以“前缀-”开头。 你可以编辑变量IfUnused, IfEmpty， 和MatchRegex根据您的要求。

另一个选项是删除与队列关联的vhost。这将删除与vhost关联的所有内容，因此请注意，但这很简单且快速。

注意:RabbitMQ团队会监控RabbitMQ用户的邮件列表，有时只在StackOverflow上回答问题。

如果你没有安装rabbitmqadmin，尝试使用rabbitmqctl清除队列:

rabbitmqctl list_queues | awk '{print $1}' | xargs -L1 rabbitmqctl purge_queue . txt