我如何在Java中用SHA-256散列一些字符串?


当前回答

我认为最简单的解决方案是使用Apache Common Codec:

String sha256hex = org.apache.commons.codec.digest.DigestUtils.sha256Hex(stringText);   

其他回答

如果你使用的是Java 8,你可以这样编码字节[]

MessageDigest digest = MessageDigest.getInstance("SHA-256");
byte[] hash = digest.digest(text.getBytes(StandardCharsets.UTF_8));
String encoded = Base64.getEncoder().encodeToString(hash);
String hashWith256(String textToHash) {
    MessageDigest digest = MessageDigest.getInstance("SHA-256");
    byte[] byteOfTextToHash = textToHash.getBytes(StandardCharsets.UTF_8);
    byte[] hashedByetArray = digest.digest(byteOfTextToHash);
    String encoded = Base64.getEncoder().encodeToString(hashedByetArray);
    return encoded;
}

我认为最简单的解决方案是使用Apache Common Codec:

String sha256hex = org.apache.commons.codec.digest.DigestUtils.sha256Hex(stringText);   

这是我使用Kotlin的方法:

private fun getHashFromEmailString(email : String) : String{
    val charset = Charsets.UTF_8
    val byteArray = email.toByteArray(charset)
    val digest = MessageDigest.getInstance("SHA-256")
    val hash = digest.digest(byteArray)

    return hash.fold("", { str, it -> str + "%02x".format(it)})
}

这是我用于哈希的:

String pass = "password";

MessageDigest messageDigest = MessageDigest.getInstance("SHA-256");
byte hashBytes[] = messageDigest.digest(pass.getBytes(StandardCharsets.UTF_8));
BigInteger noHash = new BigInteger(1, hashBytes);
String hashStr = noHash.toString(16);

输出:5e884898da28047151d0e56f8dc6292773603d0d6aabbdd62a11ef721d1542d8