我使用Laravel雄辩的查询构建器,我有一个查询,我想在多个条件上有一个where子句。它能起作用,但并不优雅。

例子:

$results = User::where('this', '=', 1)
    ->where('that', '=', 1)
    ->where('this_too', '=', 1)
    ->where('that_too', '=', 1)
    ->where('this_as_well', '=', 1)
    ->where('that_as_well', '=', 1)
    ->where('this_one_too', '=', 1)
    ->where('that_one_too', '=', 1)
    ->where('this_one_as_well', '=', 1)
    ->where('that_one_as_well', '=', 1)
    ->get();

有没有更好的方法,或者我应该坚持这个方法?


当前回答

使用Array的条件:

$users = User::where([
       'column1' => value1,
       'column2' => value2,
       'column3' => value3
])->get();

将产生如下查询:

SELECT * FROM TABLE WHERE column1 = value1 and column2 = value2 and column3 = value3

使用匿名函数的条件:

$users = User::where('column1', '=', value1)
               ->where(function($query) use ($variable1,$variable2){
                    $query->where('column2','=',$variable1)
                   ->orWhere('column3','=',$variable2);
               })
              ->where(function($query2) use ($variable1,$variable2){
                    $query2->where('column4','=',$variable1)
                   ->where('column5','=',$variable2);
              })->get();

将产生如下查询:

SELECT * FROM TABLE WHERE column1 = value1 and (column2 = value2 or column3 = value3) and (column4 = value4 and column5 = value5)

其他回答

多个where子句

    $query=DB::table('users')
        ->whereRaw("users.id BETWEEN 1003 AND 1004")
        ->whereNotIn('users.id', [1005,1006,1007])
        ->whereIn('users.id',  [1008,1009,1010]);
    $query->where(function($query2) use ($value)
    {
        $query2->where('user_type', 2)
            ->orWhere('value', $value);
    });

   if ($user == 'admin'){
        $query->where('users.user_name', $user);
    }

终于得到了结果

    $result = $query->get();

在Eloquent中,你可以这样做:

$results = User::where('this', '=', 1)
->orWhere('that', '=', 1)
->orWhere('this_too', '=', 1)
->orWhere('that_too', '=', 1)
->orWhere('this_as_well', '=', 1)
->orWhere('that_as_well', '=', 1)
->orWhere('this_one_too', '=', 1)
->orWhere('that_one_too', '=', 1)
->orWhere('this_one_as_well', '=', 1)
->orWhere('that_one_as_well', '=', 1)
->get();

在Laravel 5.3中(在7.x中仍然如此),你可以使用更细粒度的数组:

$query->where([
    ['column_1', '=', 'value_1'],
    ['column_2', '<>', 'value_2'],
    [COLUMN, OPERATOR, VALUE],
    ...
])

就我个人而言,我还没有发现这个用例超过多个where调用,但事实是你可以使用它。

自2014年6月起,您可以将数组传递到where

只要你想要所有的where use和operator,你可以这样分组:

$matchThese = ['field' => 'value', 'another_field' => 'another_value', ...];

// if you need another group of wheres as an alternative:
$orThose = ['yet_another_field' => 'yet_another_value', ...];

然后:

$results = User::where($matchThese)->get();

// with another group
$results = User::where($matchThese)
    ->orWhere($orThose)
    ->get();

以上将导致这样的查询:

SELECT * FROM users
  WHERE (field = value AND another_field = another_value AND ...)
  OR (yet_another_field = yet_another_value AND ...)

whereColumn方法可以传递一个包含多个条件的数组。这些条件将使用and操作符进行连接。

例子:

$users = DB::table('users')
            ->whereColumn([
                ['first_name', '=', 'last_name'],
                ['updated_at', '>', 'created_at']
            ])->get();

$users = User::whereColumn([
                ['first_name', '=', 'last_name'],
                ['updated_at', '>', 'created_at']
            ])->get();

有关更多信息,请查看文档的这一部分 https://laravel.com/docs/5.4/queries#where-clauses

使用纯Eloquent,像这样实现它。这段代码返回所有帐户处于活动状态的已登录用户。 $用户= \ App \用户::(“状态”,“积极”)——> (logged_in,真的)- > ();