我使用Laravel雄辩的查询构建器,我有一个查询,我想在多个条件上有一个where子句。它能起作用,但并不优雅。

例子:

$results = User::where('this', '=', 1)
    ->where('that', '=', 1)
    ->where('this_too', '=', 1)
    ->where('that_too', '=', 1)
    ->where('this_as_well', '=', 1)
    ->where('that_as_well', '=', 1)
    ->where('this_one_too', '=', 1)
    ->where('that_one_too', '=', 1)
    ->where('this_one_as_well', '=', 1)
    ->where('that_one_as_well', '=', 1)
    ->get();

有没有更好的方法,或者我应该坚持这个方法?


当前回答

多个地方

您还可以将一个条件数组传递给where函数。数组的每个元素都应该是一个数组,包含通常传递给where方法的三个参数:

Model::where([
    ['status', '=', '1'],
    ['subscribed', '<>', '1'],
])->get();

多个或Where子句

如果你需要在圆括号内对"or"条件进行分组,你可以将闭包作为第一个参数传递给orWhere方法:

Model::where('votes', '>', 100)
        ->orWhere(function ($query) {
            $query->where('name', 'abcd')
                ->orWhere(function ($query) {
                    $query->where('name', 'cdef')
                        ->where('votes', '>', 50);
                });
        })
        ->get();

上面的例子将产生以下SQL语句:

select * from `users` where `votes` > 100 or (`name` = "abcd" or (`name` = "cdef" and `votes` > 50));

多指针where with whereNot和orWhereNot方法

whereNot和orWhereNot方法可用于对给定的查询约束组求反。例如,以下查询排除清仓或价格小于10的产品:

$products = Product::where([
        ['status', '=', '1'],
        ['is_feature', '1']
    ])
        ->whereNot(function ($query) {
            $query->where('clearance', true)
                ->orWhere('price', '<', 10);
        })
        ->get();

其他回答

多个where子句

    $query=DB::table('users')
        ->whereRaw("users.id BETWEEN 1003 AND 1004")
        ->whereNotIn('users.id', [1005,1006,1007])
        ->whereIn('users.id',  [1008,1009,1010]);
    $query->where(function($query2) use ($value)
    {
        $query2->where('user_type', 2)
            ->orWhere('value', $value);
    });

   if ($user == 'admin'){
        $query->where('users.user_name', $user);
    }

终于得到了结果

    $result = $query->get();
$variable = array('this' => 1,
                    'that' => 1
                    'that' => 1,
                    'this_too' => 1,
                    'that_too' => 1,
                    'this_as_well' => 1,
                    'that_as_well' => 1,
                    'this_one_too' => 1,
                    'that_one_too' => 1,
                    'this_one_as_well' => 1,
                    'that_one_as_well' => 1);

foreach ($variable as $key => $value) {
    User::where($key, '=', $value);
}

使用纯Eloquent,像这样实现它。这段代码返回所有帐户处于活动状态的已登录用户。 $用户= \ App \用户::(“状态”,“积极”)——> (logged_in,真的)- > ();

在Eloquent中,你可以这样做:

$results = User::where('this', '=', 1)
->orWhere('that', '=', 1)
->orWhere('this_too', '=', 1)
->orWhere('that_too', '=', 1)
->orWhere('this_as_well', '=', 1)
->orWhere('that_as_well', '=', 1)
->orWhere('this_one_too', '=', 1)
->orWhere('that_one_too', '=', 1)
->orWhere('this_one_as_well', '=', 1)
->orWhere('that_one_as_well', '=', 1)
->get();

使用这个

$users = DB::table('users')
                    ->where('votes', '>', 100)
                    ->orWhere('name', 'John')
                    ->get();