我使用Laravel雄辩的查询构建器，我有一个查询，我想在多个条件上有一个where子句。它能起作用，但并不优雅。
例子:
$results = User::where('this', '=', 1)
->where('that', '=', 1)
->where('this_too', '=', 1)
->where('that_too', '=', 1)
->where('this_as_well', '=', 1)
->where('that_as_well', '=', 1)
->where('this_one_too', '=', 1)
->where('that_one_too', '=', 1)
->where('this_one_as_well', '=', 1)
->where('that_one_as_well', '=', 1)
->get();
有没有更好的方法，或者我应该坚持这个方法?
当前回答
$variable = array('this' => 1,
'that' => 1
'that' => 1,
'this_too' => 1,
'that_too' => 1,
'this_as_well' => 1,
'that_as_well' => 1,
'this_one_too' => 1,
'that_one_too' => 1,
'this_one_as_well' => 1,
'that_one_as_well' => 1);
foreach ($variable as $key => $value) {
User::where($key, '=', $value);
}
其他回答
多个where子句
$query=DB::table('users')
->whereRaw("users.id BETWEEN 1003 AND 1004")
->whereNotIn('users.id', [1005,1006,1007])
->whereIn('users.id', [1008,1009,1010]);
$query->where(function($query2) use ($value)
{
$query2->where('user_type', 2)
->orWhere('value', $value);
});
if ($user == 'admin'){
$query->where('users.user_name', $user);
}
终于得到了结果
$result = $query->get();
$variable = array('this' => 1,
'that' => 1
'that' => 1,
'this_too' => 1,
'that_too' => 1,
'this_as_well' => 1,
'that_as_well' => 1,
'this_one_too' => 1,
'that_one_too' => 1,
'this_one_as_well' => 1,
'that_one_as_well' => 1);
foreach ($variable as $key => $value) {
User::where($key, '=', $value);
}
whereColumn方法可以传递一个包含多个条件的数组。这些条件将使用and操作符进行连接。
例子:
$users = DB::table('users')
->whereColumn([
['first_name', '=', 'last_name'],
['updated_at', '>', 'created_at']
])->get();
$users = User::whereColumn([
['first_name', '=', 'last_name'],
['updated_at', '>', 'created_at']
])->get();
有关更多信息，请查看文档的这一部分 https://laravel.com/docs/5.4/queries#where-clauses
根据我的建议，如果你正在做筛选或搜索
那么你应该选择:
$results = User::query();
$results->when($request->that, function ($q) use ($request) {
$q->where('that', $request->that);
});
$results->when($request->this, function ($q) use ($request) {
$q->where('this', $request->that);
});
$results->when($request->this_too, function ($q) use ($request) {
$q->where('this_too', $request->that);
});
$results->get();
你可以这样做，这是最短的方法。
$results = User::where(['this'=>1,
'that'=>1,
'this_too'=>1,
'that_too'=>1,
'this_as_well'=>1,
'that_as_well'=>1,
'this_one_too'=>1,
'that_one_too'=>1,
'this_one_as_well'=>1,
'that_one_as_well'=>1])->get();
