我正在创建一个网页,其中我有一个输入文本字段,我想只允许数字字符,如(0,1,2,3,4,5…9)0-9。

我如何使用jQuery做到这一点?


当前回答

$(document).ready(function()
{
    $("#textBoxId").bind("change",checkInput);
});

function checkInput()
{
    // check if $('#textBoxId').val() is under your constraints
    // then change its value, removing the last character
    // since this event will be called each time you
    // type a character
}

其他回答

这是我用来验证整数或浮点值的数字输入(不显眼的jQuery风格):

$('input[name="number"]').keyup(function(e) { var float = parseFloat($(this).attr('data-float')); /* 2 regexp for validating integer and float inputs ***** > integer_regexp : allow numbers, but do not allow leading zeros > float_regexp : allow numbers + only one dot sign (and only in the middle of the string), but do not allow leading zeros in the integer part *************************************************************************/ var integer_regexp = (/[^0-9]|^0+(?!$)/g); var float_regexp = (/[^0-9\.]|^\.+(?!$)|^0+(?=[0-9]+)|\.(?=\.|.+\.)/g); var regexp = (float % 1 === 0) ? integer_regexp : float_regexp; if (regexp.test(this.value)) { this.value = this.value.replace(regexp, ''); } }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input type="text" data-float="1" id="number" name="number" placeholder="integer"> <input type="text" data-float="0.1" id="number" name="number" placeholder="float">

function validate_profile(frmid) {
    var form = $('#' + frmid);
    var error = $('.alert-danger', form);
    var success = $('.alert-success', form);
    form.validate({
        errorElement: 'span', //default input error message container
        errorClass: 'help-block', // default input error message class
        focusInvalid: true, // do not focus the last invalid input
        ignore: "",
        rules: {
            contact_no: {
                required: true,
                minlength: 10,
                maxlength: 10,
                number: true
            }, email_id: {
                required: true,
                email: true
            }
        },
        invalidHandler: function (event, validator) { //display error alert on form submit   
            success.hide();
            error.show();
            Metronic.scrollTo(error, -7000);
        },
        highlight: function (element) { // hightlight error inputs
            $(element)
                    .closest('.form-group').addClass('has-error'); // un set error class to the control group
            $(element)
                    .closest('.form-group').removeClass('has-success'); // set success class to the control group
        },
        unhighlight: function (element) { // revert the change done by hightlight
            $(element)
                    .closest('.form-group').removeClass('has-error'); // un set error class to the control group
            $(element)
                    .closest('.form-group').addClass('has-success'); // set success class to the control group
            error.hide();
        },
        success: function (label) {
            label.closest('.form-group').removeClass('has-error');
            label.closest('.form-group').addClass('has-success');
        },
        submitHandler: function (form) {
            success.show();
            error.hide();
            form.submit();
        }
    });
}

我把所有的答案结合在一起,得出了以下代码:

jQuery('#input_id', function(e){
    // Allow: backspace, delete, tab, escape, enter
    if (jQuery.inArray(e.keyCode, [46, 8, 9, 27, 13, 110]) !== -1 ||
        // Allow: Ctrl+A
        (e.keyCode === 65 && e.ctrlKey === true) ||
        // Allow: Ctrl+C
        (e.keyCode === 67 && e.ctrlKey === true) ||
        // Allow: Ctrl+X
        (e.keyCode === 88 && e.ctrlKey === true) ||
        // Disallow several dots (allow 190 only if no dots found)
        (e.keyCode === 190 && jQuery(this).val().indexOf('.') == -1) ||
        // Bug in some Android devices where it is always 229
        (e.keyCode === 229) ||
        // Allow: home, end, left, right
        (e.keyCode >= 35 && e.keyCode <= 40)) {
        // let it happen, don't do anything
        return;
    }
    // Ensure that it is a number and stop the keypress
    if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) && (e.keyCode < 96 || e.keyCode > 105)) {
        e.preventDefault();
    }
});

此外,表单应该有autocomplete="off"。如果没有这个选项,你可能会在移动设备上遇到自动补全算法的问题。

我想帮点忙,我做了我的版本,onlyNumbers函数…

function onlyNumbers(e){
    var keynum;
    var keychar;

    if(window.event){  //IE
        keynum = e.keyCode;
    }
    if(e.which){ //Netscape/Firefox/Opera
        keynum = e.which;
    }
    if((keynum == 8 || keynum == 9 || keynum == 46 || (keynum >= 35 && keynum <= 40) ||
       (event.keyCode >= 96 && event.keyCode <= 105)))return true;

    if(keynum == 110 || keynum == 190){
        var checkdot=document.getElementById('price').value;
        var i=0;
        for(i=0;i<checkdot.length;i++){
            if(checkdot[i]=='.')return false;
        }
        if(checkdot.length==0)document.getElementById('price').value='0';
        return true;
    }
    keychar = String.fromCharCode(keynum);

    return !isNaN(keychar);
}

只需添加输入标签“…输入……id="price" onkeydown="return onlyNumbers(event)"…"然后你就完成了;)

很多人在这里使用键码属性,这是不容易记住的。如果你没有语言环境问题,那么你可以简单地使用键,这实际上是用户键入的输入。

看这把小提琴

$("#txt").on("keypress",function(e){ console.log("Entered Key is " + e.key); switch (e.key) { case "1": case "2": case "3": case "4": case "5": case "6": case "7": case "8": case "9": case "0": case "Backspace": return true; break; case ".": if ($(this).val().indexOf(".") == -1) //Checking if it already contains decimal. You can Remove this condition if you do not want to include decimals in your input box. { return true; } else { return false; } break; default: return false; } }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> Enter Value <input id="txt" type="text" />

然后查看下面的简单代码。

请注意,此示例还包含对十进制输入的验证。

对于这个问题,它不是必需的,所以您可以简单地删除大小写“。”以删除小数的条目。