我有一个JavaScript数组,如:

[["$6"], ["$12"], ["$25"], ["$25"], ["$18"], ["$22"], ["$10"]]

如何将单独的内部数组合并为一个,例如:

["$6", "$12", "$25", ...]

当前回答

最好是以递归的方式执行,这样如果另一个数组中还有另一个,就可以很容易地过滤。。。

const flattenArray = arr =>
  arr.reduce(
    (res, cur) =>
       !Array.isArray(cur) 
       ? res.concat(cur)
       : res.concat(flattenArray(cur)), []);

你可以这样称呼它:

flattenArray([[["Alireza"], "Dezfoolian"], ["is a"], ["developer"], [[1, [2, 3], ["!"]]]);

结果如下:

["Alireza", "Dezfoolian", "is a", "developer", 1, 2, 3, "!"]

其他回答

您可以使用“join()”和“split()”:

设arrs=[["$6"],["$12"],["$25"],["$25"],["$18"],["$22"],["$10"]];让newArr=arrs.join(“,”).split(“,“);console.log(newArr);//["$6", "$12", "$25", "$25", "$18", "$22", "$10"]

此外,还可以使用“toString()”和“split()”:

设arrs=[["$6"],["$12"],["$25"],["$25"],["$18"],["$22"],["$10"]];让newArr=arrs.toString().split(“,”);console.log(newArr);//["$6", "$12", "$25", "$25", "$18", "$22", "$10"]

然而,如果字符串包含逗号,上述两种方式都不能正常工作:

“join()”和“split()”:

设arrs=[["$,6"],["$,12"],["$2,5"],["$2,5"],[",$18"],["$22,"],["$,1,0"]];让newArr=arrs.join(“,”).split(“,“);console.log(newArr);// ["$", "6", "$", "12", "$2", "5", "$2", "5", "", "$18", "$22", "", "$", "1", "0"]

“toString()”和“split()”:

设arrs=[["$,6"],["$,12"],["$2,5"],["$2,5"],[",$18"],["$22,"],["$,1,0"]];让newArr=arrs.toString().split(“,”);console.log(newArr);// ["$", "6", "$", "12", "$2", "5", "$2", "5", "", "$18", "$22", "", "$", "1", "0"]

const flatten = array => array.reduce((a, b) => a.concat(Array.isArray(b) ? flatten(b) : b), []); 

根据请求,分解一行基本上就是这样。

function flatten(array) {
  // reduce traverses the array and we return the result
  return array.reduce(function(acc, b) {
     // if is an array we use recursion to perform the same operations over the array we found 
     // else we just concat the element to the accumulator
     return acc.concat( Array.isArray(b) ? flatten(b) : b);
  }, []); // we initialize the accumulator on an empty array to collect all the elements
}

我建议使用节省空间的发电机功能:

函数*展平(arr){如果(!Array.isArray(arr))产生arr;否则为(设arr的el)屈服*展平(el);}//示例:console.log(…flatten([1,[2,[3,[4]]]));//1 2 3 4

如果需要,请创建一个展平值数组,如下所示:

let flattened = [...flatten([1,[2,[3,[4]]]])]; // [1, 2, 3, 4]
const common = arr.reduce((a, b) => [...a, ...b], [])
let arr = [1, [2, 3, [4, 5, [6, 7], [8, 9, 10, 11, 12]]]];

function flattenList(nestedArr) {
  let newFlattenList = [];

  const handleFlat = (array) => {
    let count = 0;
    while (count < array.length) {
      let item = array[count];
      if (Array.isArray(item)) {
        handleFlat(item);
      } else {
        newFlattenList.push(item);
      }
      count++;
    }
  };
  handleFlat(nestedArr);
  return newFlattenList;
}`enter code here`

console.log(flattenList(arr));

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