如何使用PHP获取客户端IP地址?
我想通过他/她的IP地址登录到我的网站的用户的记录。
如何使用PHP获取客户端IP地址?
我想通过他/她的IP地址登录到我的网站的用户的记录。
当前回答
以下是我发现的最先进的方法,我在过去已经尝试过其他一些方法。确保获得访问者的IP地址是有效的(但请注意,任何黑客都很容易伪造IP地址)。
function get_ip_address() {
// Check for shared Internet/ISP IP
if (!empty($_SERVER['HTTP_CLIENT_IP']) && validate_ip($_SERVER['HTTP_CLIENT_IP'])) {
return $_SERVER['HTTP_CLIENT_IP'];
}
// Check for IP addresses passing through proxies
if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
// Check if multiple IP addresses exist in var
if (strpos($_SERVER['HTTP_X_FORWARDED_FOR'], ',') !== false) {
$iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
foreach ($iplist as $ip) {
if (validate_ip($ip))
return $ip;
}
}
else {
if (validate_ip($_SERVER['HTTP_X_FORWARDED_FOR']))
return $_SERVER['HTTP_X_FORWARDED_FOR'];
}
}
if (!empty($_SERVER['HTTP_X_FORWARDED']) && validate_ip($_SERVER['HTTP_X_FORWARDED']))
return $_SERVER['HTTP_X_FORWARDED'];
if (!empty($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']) && validate_ip($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']))
return $_SERVER['HTTP_X_CLUSTER_CLIENT_IP'];
if (!empty($_SERVER['HTTP_FORWARDED_FOR']) && validate_ip($_SERVER['HTTP_FORWARDED_FOR']))
return $_SERVER['HTTP_FORWARDED_FOR'];
if (!empty($_SERVER['HTTP_FORWARDED']) && validate_ip($_SERVER['HTTP_FORWARDED']))
return $_SERVER['HTTP_FORWARDED'];
// Return unreliable IP address since all else failed
return $_SERVER['REMOTE_ADDR'];
}
/**
* Ensures an IP address is both a valid IP address and does not fall within
* a private network range.
*/
function validate_ip($ip) {
if (strtolower($ip) === 'unknown')
return false;
// Generate IPv4 network address
$ip = ip2long($ip);
// If the IP address is set and not equivalent to 255.255.255.255
if ($ip !== false && $ip !== -1) {
// Make sure to get unsigned long representation of IP address
// due to discrepancies between 32 and 64 bit OSes and
// signed numbers (ints default to signed in PHP)
$ip = sprintf('%u', $ip);
// Do private network range checking
if ($ip >= 0 && $ip <= 50331647)
return false;
if ($ip >= 167772160 && $ip <= 184549375)
return false;
if ($ip >= 2130706432 && $ip <= 2147483647)
return false;
if ($ip >= 2851995648 && $ip <= 2852061183)
return false;
if ($ip >= 2886729728 && $ip <= 2887778303)
return false;
if ($ip >= 3221225984 && $ip <= 3221226239)
return false;
if ($ip >= 3232235520 && $ip <= 3232301055)
return false;
if ($ip >= 4294967040)
return false;
}
return true;
}
其他回答
在这一点上,我很惊讶它还没有被提及,就是获得那些位于CloudFlare基础设施后面的网站的正确IP地址。它将打破你的IP地址,并给他们所有相同的值。 幸运的是,他们也有一些可用的服务器头。 与其我重写已经写过的东西,不如看看这里的一个更简洁的答案,是的,我很久以前也经历过这个过程。 https://stackoverflow.com/a/14985633/1190051
这是我使用的方法,它验证IPv4输入:
// Get user IP address
if ( isset($_SERVER['HTTP_CLIENT_IP']) && ! empty($_SERVER['HTTP_CLIENT_IP'])) {
$ip = $_SERVER['HTTP_CLIENT_IP'];
} elseif ( isset($_SERVER['HTTP_X_FORWARDED_FOR']) && ! empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
$ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else {
$ip = (isset($_SERVER['REMOTE_ADDR'])) ? $_SERVER['REMOTE_ADDR'] : '0.0.0.0';
}
$ip = filter_var($ip, FILTER_VALIDATE_IP);
$ip = ($ip === false) ? '0.0.0.0' : $ip;
echo $_SERVER['REMOTE_ADDR'];
http://php.net/manual/en/reserved.variables.server.php
快速解决方案(无错误)
function getClientIP():string
{
$keys=array('HTTP_CLIENT_IP','HTTP_X_FORWARDED_FOR','HTTP_X_FORWARDED','HTTP_FORWARDED_FOR','HTTP_FORWARDED','REMOTE_ADDR');
foreach($keys as $k)
{
if (!empty($_SERVER[$k]) && filter_var($_SERVER[$k], FILTER_VALIDATE_IP))
{
return $_SERVER[$k];
}
}
return "UNKNOWN";
}
试试这个:
$_SERVER['REMOTE_ADDR'];