我想将Swift中的Int转换为带前导零的字符串。例如,考虑以下代码:

for myInt in 1 ... 3 {
    print("\(myInt)")
}

目前的结果是:

1
2
3

但我希望它是:

01
02
03

在Swift标准库中是否有一种干净的方式来做到这一点?


当前回答

细节

Xcode 9.0.1, swift 4.0

解决方案

Data

import Foundation

let array = [0,1,2,3,4,5,6,7,8]

解决方案1

extension Int {

    func getString(prefix: Int) -> String {
        return "\(prefix)\(self)"
    }

    func getString(prefix: String) -> String {
        return "\(prefix)\(self)"
    }
}

for item in array {
    print(item.getString(prefix: 0))
}

for item in array {
    print(item.getString(prefix: "0x"))
}

解决方案2

for item in array {
    print(String(repeatElement("0", count: 2)) + "\(item)")
}

解决方案3

extension String {

    func repeate(count: Int, string: String? = nil) -> String {

        if count > 1 {
            let repeatedString = string ?? self
            return repeatedString + repeate(count: count-1, string: repeatedString)
        }
        return self
    }
}

for item in array {
    print("0".repeate(count: 3) + "\(item)")
}

其他回答

假设你想要一个长度为2且前导为0的字段,你可以这样做:

import Foundation

for myInt in 1 ... 3 {
    print(String(format: "%02d", myInt))
}

输出:

01 02 03

这需要导入Foundation,所以从技术上讲,它不是Swift语言的一部分,而是Foundation框架提供的功能。请注意,import UIKit和import Cocoa都包含Foundation,所以如果你已经导入了Cocoa或UIKit,就没有必要再次导入它。


格式字符串可以指定多个项的格式。例如,如果你想把3小时15分7秒格式化为03:15:07,你可以这样做:

let hours = 3
let minutes = 15
let seconds = 7
print(String(format: "%02d:%02d:%02d", hours, minutes, seconds))

输出:

03:15:07

对于左填充,添加一个字符串扩展,如下所示:

Swift 5.0 +

extension String {

    func padLeft(totalWidth: Int, with byString: String) -> String {
        let toPad = totalWidth - self.count
        if toPad < 1 {
            return self
        }
    
        return "".padding(toLength: toPad, withPad: byString, startingAt: 0) + self
    }
}

使用这种方法:

for myInt in 1...3 {
    print("\(myInt)".padLeft(totalWidth: 2, with: "0"))
}

斯威夫特5

@imanuo answers已经很棒了,但如果你正在使用一个充满数字的应用程序,你可以考虑这样的扩展:

extension String {

    init(withInt int: Int, leadingZeros: Int = 2) {
        self.init(format: "%0\(leadingZeros)d", int)
    }

    func leadingZeros(_ zeros: Int) -> String {
        if let int = Int(self) {
            return String(withInt: int, leadingZeros: zeros)
        }
        print("Warning: \(self) is not an Int")
        return ""
    }
    
}

这样你可以在任何地方打电话:

String(withInt: 3) 
// prints 03

String(withInt: 23, leadingZeros: 4) 
// prints 0023

"42".leadingZeros(2)
// prints 42

"54".leadingZeros(3)
// prints 054

Swift 4*及以上,你也可以试试这个:

func leftPadding(valueString: String, toLength: Int, withPad: String = " ") -> String {
        guard toLength > valueString.count else { return valueString }
        
        let padding = String(repeating: withPad, count: toLength - valueString.count)
        return padding + valueString
    }

调用函数:

leftPadding(valueString: "12", toLength: 5, withPad: "0")

输出: “00012”

在Xcode 8.3.2, iOS 10.3 这对现在来说很好

Sample1:

let dayMoveRaw = 5 
let dayMove = String(format: "%02d", arguments: [dayMoveRaw])
print(dayMove) // 05

Sample2:

let dayMoveRaw = 55 
let dayMove = String(format: "%02d", arguments: [dayMoveRaw])
print(dayMove) // 55