我想将一个数组的元素添加到另一个数组中,所以我尝试了这样做:

[1,2] + [3,4]

它的答复是:

"1,23,4"

这是怎么回事?


当前回答

这完全是你让它做的。

你加在一起的是数组引用(JS将其转换为字符串),而不是看起来的数字。这有点像字符串相加:"hello " + "world" = "hello world"

其他回答

它像添加字符串一样添加两个数组。

第一个数组的字符串表示形式是“1,2”,第二个数组是“3,4”。因此,当找到+号时,它不能对数组求和,然后将它们作为字符串连接起来。

看起来JavaScript正在将数组转换为字符串并将它们连接在一起。如果要将元组添加到一起,则必须使用循环或映射函数。

Some answers here have explained how the unexpected undesired output ('1,23,4') happens and some have explained how to obtain what they assume to be the expected desired output ([1,2,3,4]), i.e. array concatenation. However, the nature of the expected desired output is actually somewhat ambiguous because the original question simply states "I wanted to add the elements of an array into another...". That could mean array concatenation but it could also mean tuple addition (e.g. here and here), i.e. adding the scalar values of elements in one array to the scalar values of the corresponding elements in the second, e.g. combining [1,2] and [3,4] to obtain [4,6].

假设两个数组都有相同的arity/length,这里有一个简单的解决方案:

Const arr1 = [1,2]; Const arr2 = [3,4]; Const add = (a1, a2) => a1。Map ((e, i) => e + a2[i]); console.log(添加(arr1 arr2));// ==> [4,6]

另一个使用简单的“+”符号的结果是:

[1,2]+','+[3,4] === [1,2,3,4]

所以像这样的东西应该工作(但是!):

var a=[1,2];
var b=[3,4];
a=a+','+b; // [1,2,3,4]

... 但它会将变量a从数组转换为字符串!记住这一点。

这完全是你让它做的。

你加在一起的是数组引用(JS将其转换为字符串),而不是看起来的数字。这有点像字符串相加:"hello " + "world" = "hello world"