是否斯威夫特有一个修剪方法的字符串?例如:

let result = " abc ".trim()
// result == "abc"

当前回答

在Swift3 XCode 8 Final中

注意CharacterSet。空格不再是函数了!

(NSCharacterSet.whitespaces也不是)

extension String {
    func trim() -> String {
        return self.trimmingCharacters(in: CharacterSet.whitespaces)
    }
}

其他回答

不要忘记导入Foundation或UIKit。

import Foundation
let trimmedString = "   aaa  "".trimmingCharacters(in: .whitespaces)
print(trimmedString)

结果:

"aaa"

否则你会得到:

error: value of type 'String' has no member 'trimmingCharacters'
    return self.trimmingCharacters(in: .whitespaces)

//Swift 4.0删除空格和新行

extension String {
    func trim() -> String {
        return self.trimmingCharacters(in: .whitespacesAndNewlines)         
    }
}

您还可以发送您想要修剪的字符

extension String {


    func trim() -> String {

        return self.trimmingCharacters(in: .whitespacesAndNewlines)

    }

    func trim(characterSet:CharacterSet) -> String {

        return self.trimmingCharacters(in: characterSet)

    }
}

validationMessage = validationMessage.trim(characterSet: CharacterSet(charactersIn: ","))

Swift 5和4.2

let trimmedString = " abc ".trimmingCharacters(in: .whitespaces)
 //trimmedString == "abc"

斯威夫特3

let result = " abc ".trimmingCharacters(in: .whitespacesAndNewlines)