例子:

absolute="/foo/bar"
current="/foo/baz/foo"

# Magic

relative="../../bar"

我如何创造魔法(希望不是太复杂的代码…)?


当前回答

该脚本仅对绝对路径或没有绝对路径的相对路径的输入提供正确的结果。或者. .:

#!/bin/bash

# usage: relpath from to

if [[ "$1" == "$2" ]]
then
    echo "."
    exit
fi

IFS="/"

current=($1)
absolute=($2)

abssize=${#absolute[@]}
cursize=${#current[@]}

while [[ ${absolute[level]} == ${current[level]} ]]
do
    (( level++ ))
    if (( level > abssize || level > cursize ))
    then
        break
    fi
done

for ((i = level; i < cursize; i++))
do
    if ((i > level))
    then
        newpath=$newpath"/"
    fi
    newpath=$newpath".."
done

for ((i = level; i < abssize; i++))
do
    if [[ -n $newpath ]]
    then
        newpath=$newpath"/"
    fi
    newpath=$newpath${absolute[i]}
done

echo "$newpath"

其他回答

$ python -c "import os.path; print os.path.relpath('/foo/bar', '/foo/baz/foo')"

给:

../../bar

test.sh:

#!/bin/bash                                                                 

cd /home/ubuntu
touch blah
TEST=/home/ubuntu/.//blah
echo TEST=$TEST
TMP=$(readlink -e "$TEST")
echo TMP=$TMP
REL=${TMP#$(pwd)/}
echo REL=$REL

测试:

$ ./test.sh 
TEST=/home/ubuntu/.//blah
TMP=/home/ubuntu/blah
REL=blah

自2001年以来,它被内置到Perl中,因此它几乎可以在您能想象到的所有系统上工作,甚至VMS。

perl -le 'use File::Spec; print File::Spec->abs2rel(@ARGV)' FILE BASE

而且,解决方案很容易理解。

举个例子:

perl -le 'use File::Spec; print File::Spec->abs2rel(@ARGV)' $absolute $current

...会很好。

另一个解决方案,纯bash + GNU readlink,在以下上下文中易于使用:

ln -s "$(relpath "$A" "$B")" "$B"

编辑:确保“$B”是不存在或没有软链接在这种情况下,否则relpath遵循这个链接,这不是你想要的!

这几乎适用于当前所有的Linux。如果readlink -m在您这边不起作用,请尝试readlink -f。请参见https://gist.github.com/hilbix/1ec361d00a8178ae8ea0查看可能的更新:

: relpath A B
# Calculate relative path from A to B, returns true on success
# Example: ln -s "$(relpath "$A" "$B")" "$B"
relpath()
{
local X Y A
# We can create dangling softlinks
X="$(readlink -m -- "$1")" || return
Y="$(readlink -m -- "$2")" || return
X="${X%/}/"
A=""
while   Y="${Y%/*}"
        [ ".${X#"$Y"/}" = ".$X" ]
do
        A="../$A"
done
X="$A${X#"$Y"/}"
X="${X%/}"
echo "${X:-.}"
}

注:

Care was taken that it is safe against unwanted shell meta character expansion, in case filenames contain * or ?. The output is meant to be usable as the first argument to ln -s: relpath / / gives . and not the empty string relpath a a gives a, even if a happens to be a directory Most common cases were tested to give reasonable results, too. This solution uses string prefix matching, hence readlink is required to canonicalize paths. Thanks to readlink -m it works for not yet existing paths, too.

在旧系统上,readlink -m不可用,如果文件不存在,readlink -f将失败。所以你可能需要一些像这样的解决方法(未经测试!):

readlink_missing()
{
readlink -m -- "$1" && return
readlink -f -- "$1" && return
[ -e . ] && echo "$(readlink_missing "$(dirname "$1")")/$(basename "$1")"
}

这在$1包含的情况下是不正确的。或. .对于不存在的路径(如/doesnotexist/./a),但它应该涵盖大多数情况。

(用readlink_missing替换上面的readlink -m——)

编辑,因为下面是反对票

下面是一个测试,这个函数确实是正确的:

check()
{
res="$(relpath "$2" "$1")"
[ ".$res" = ".$3" ] && return
printf ':WRONG: %-10q %-10q gives %q\nCORRECT %-10q %-10q gives %q\n' "$1" "$2" "$res" "$@"
}

#     TARGET   SOURCE         RESULT
check "/A/B/C" "/A"           ".."
check "/A/B/C" "/A.x"         "../../A.x"
check "/A/B/C" "/A/B"         "."
check "/A/B/C" "/A/B/C"       "C"
check "/A/B/C" "/A/B/C/D"     "C/D"
check "/A/B/C" "/A/B/C/D/E"   "C/D/E"
check "/A/B/C" "/A/B/D"       "D"
check "/A/B/C" "/A/B/D/E"     "D/E"
check "/A/B/C" "/A/D"         "../D"
check "/A/B/C" "/A/D/E"       "../D/E"
check "/A/B/C" "/D/E/F"       "../../D/E/F"

check "/foo/baz/moo" "/foo/bar" "../bar"

困惑吗?好吧,这是正确的结果!即使你认为它不符合问题,以下是正确的证明:

check "http://example.com/foo/baz/moo" "http://example.com/foo/bar" "../bar"

毫无疑问,……/bar是从页面moo中看到的页面栏的准确且唯一正确的相对路径。其他一切都是完全错误的。

采用问题的输出很简单,显然假设current是一个目录:

absolute="/foo/bar"
current="/foo/baz/foo"
relative="../$(relpath "$absolute" "$current")"

这将返回所请求的内容。

在你感到惊讶之前,这里有一个稍微复杂一点的relpath变体(注意细微的区别),它也应该适用于url语法(因此,由于一些bash魔法,末尾/幸存下来):

# Calculate relative PATH to the given DEST from the given BASE
# In the URL case, both URLs must be absolute and have the same Scheme.
# The `SCHEME:` must not be present in the FS either.
# This way this routine works for file paths an
: relpathurl DEST BASE
relpathurl()
{
local X Y A
# We can create dangling softlinks
X="$(readlink -m -- "$1")" || return
Y="$(readlink -m -- "$2")" || return
X="${X%/}/${1#"${1%/}"}"
Y="${Y%/}${2#"${2%/}"}"
A=""
while   Y="${Y%/*}"
        [ ".${X#"$Y"/}" = ".$X" ]
do
        A="../$A"
done
X="$A${X#"$Y"/}"
X="${X%/}"
echo "${X:-.}"
}

这里有一些检查,只是为了弄清楚:它确实像所说的那样工作。

check()
{
res="$(relpathurl "$2" "$1")"
[ ".$res" = ".$3" ] && return
printf ':WRONG: %-10q %-10q gives %q\nCORRECT %-10q %-10q gives %q\n' "$1" "$2" "$res" "$@"
}

#     TARGET   SOURCE         RESULT
check "/A/B/C" "/A"           ".."
check "/A/B/C" "/A.x"         "../../A.x"
check "/A/B/C" "/A/B"         "."
check "/A/B/C" "/A/B/C"       "C"
check "/A/B/C" "/A/B/C/D"     "C/D"
check "/A/B/C" "/A/B/C/D/E"   "C/D/E"
check "/A/B/C" "/A/B/D"       "D"
check "/A/B/C" "/A/B/D/E"     "D/E"
check "/A/B/C" "/A/D"         "../D"
check "/A/B/C" "/A/D/E"       "../D/E"
check "/A/B/C" "/D/E/F"       "../../D/E/F"

check "/foo/baz/moo" "/foo/bar" "../bar"
check "http://example.com/foo/baz/moo" "http://example.com/foo/bar" "../bar"

check "http://example.com/foo/baz/moo/" "http://example.com/foo/bar" "../../bar"
check "http://example.com/foo/baz/moo"  "http://example.com/foo/bar/" "../bar/"
check "http://example.com/foo/baz/moo/"  "http://example.com/foo/bar/" "../../bar/"

下面是如何用它从问题中得到想要的结果:

absolute="/foo/bar"
current="/foo/baz/foo"
relative="$(relpathurl "$absolute" "$current/")"
echo "$relative"

如果你发现什么东西不起作用,请在下面的评论中告诉我。谢谢。

PS:

为什么relpath的论点与这里的所有其他答案相反?

如果你改变

Y="$(readlink -m -- "$2")" || return

to

Y="$(readlink -m -- "${2:-"$PWD"}")" || return

然后你可以去掉第二个参数,这样BASE就是当前目录/URL/任何东西。这只是Unix的原则。

使用GNU coreutils 8.23中的realpath是最简单的,我认为:

$ realpath --relative-to="$file1" "$file2"

例如:

$ realpath --relative-to=/usr/bin/nmap /tmp/testing
../../../tmp/testing